What the person said up above should be correct!
1. H
2. A
3. E
4. C
I have to type extra words to turn this in so basically I just found the slop of the line then matched it with the letters...
Let me explain like this .Suppose There are 40 people gathered somewhere for attending an event.Each Person has to be given 2 sweets for their arrival or for showing their presence in the event. Now 40 other woman joined them..Instead of getting two sweets each of them got one sweet.
Solution: 2 sweets × 40 people = 1 sweet × 80 people = 80
2nd Way:
There are 40 rooms in a building.In Each room we have to fix two bulbs. So How many bulbs are there in the building.
Solution →→→2 bulbs × 40 room = 80 bulbs
Diagram is depicted below for two parts.
Answer:
-10, -6, 3, 4, 7
Step-by-step explanation:
Hope it helps ^^
Answer:
About 41.5%
Step-by-step explanation:
<em>Given:</em>
<em>A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape.</em>
<em>To Find:</em>
<em>What is the probability that both grapes are red?</em>
<em>Answer choices:</em>
<em>about 39.7%</em>
<em>about 41.5%</em>
<em>about 42.5%</em>
<em>about 44.5%</em>
<em>Solution:</em>
<em>Since, there are 8 green grapes and 15 red grapes, the total number of grapes is 23 .</em>
<em>As the red grapes are 15..</em>
<em>Thus,</em>
<em>The probability of choosing a red grape the first time is 15/23.</em>
<em>Because out of the total 23 grapes only 15 were red grape.</em>
<em>The probability of choosing the red grape the second time will be 14/22. Because the number of red grapes has already decreased by one and so is the total number of grapes after first choice</em>
<em>Hence, the probability of choosing or eating two red grapes will be :</em>
<em>15/23×14/22</em>
<em>=105/253</em>
<em>=0.415</em>
<em>= 41.5%</em>
<em>Therefore, the probability that both grapes are red is about 41.5%</em>
