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djverab [1.8K]
3 years ago
10

Find a parametrization of the line in which the planes x + y + z = -6 and y + z = -8 intersect.

Mathematics
1 answer:
rewona [7]3 years ago
6 0

Answer:

L(x,y) = (2,-8,0) + (0,-1,1)*t

Step-by-step explanation:

for the planes

x + y + z = -6  and y + z = -8

the intersection can be found subtracting the equation of the planes

x + y + z - ( y + z ) = -6 - (-8)

x= 2

therefore

x=2

z=z

y= -8 - z

using z as parameter t and the point (2,-8,0) as reference point , then

x= 2

y= -8 - t

z= 0 + t

another way of writing it is

L(x,y) = (2,-8,0) + (0,-1,1)*t

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The graph represents the piecewise function
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The piece-wise function is defined as follows:

  • f(x) = x^2, 0 \leq x < 3.
  • f(x) = -\frac{5}{3}x + 14, 3 < x \leq 6.
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<h3>What is a piece-wise function?</h3>

A piece-wise function is a function that has multiple definitions, depending on the input.

In this graph, for x at least 0 and less than 3, the parabolic curve passes through (0,0), (1,1), (2,4) and has an open interval at (3,9), hence the definition is:

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10 = \frac{3}{2}(10) + b

10 = 15 + b

b = -5.

Hence:

f(x) = \frac{3}{2}x - 5, 6 \leq x \leq 10

More can be learned about piece-wise functions at brainly.com/question/24734454

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