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Oksana_A [137]
3 years ago
10

Describe markings on a road that indicate that it is safe to pass.

Computers and Technology
1 answer:
hammer [34]3 years ago
5 0
You can only pass if the broken yellow line is on your side of the road. 

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Your principal has hired you to design a drone that can monitor students in the hallways. Before you brainstorm design ideas, yo
torisob [31]
It’s gonna be Answer B because all the other answers just sound silly
8 0
3 years ago
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Two boxes overlap if their interiors have at least one point in common. Give an O(n log n)-time algorithm that decides if there
GaryK [48]

Answer:

// Program is written in C++ programming language

// The program checks if two boxes overlap and prints both boxes

// Comments are used for explanatory purpose

// Program starts here

#include<bits/stdc++.h>

#include <graphics.h>

#include <conio.h>

// Define x and y axis

struct axis { int x, y; };

bool checkRect(Axis l1, Axis r1, Axis l2, Axis r2)

{ // l1, l2, r1 and r2 represent the left and right coordinates of both rectangles

// Check one rectangle is on left side of other

if (l1.x > r2.x || l2.x > r1.x) {

return false; }

// Check if one rectangle is above other

if (l1.y < r2.y || l2.y < r1.y) {

return false; }

return true;

}

// Main Method begins here

int main()

{

// Declare integer variables to enter rectangle coordinates

// For rectangle 1

int left1, left2, right1, right2;

cout<<"Enter First rectangle coordinates: "<<"\n";

cout<<"Top Left: "<<"\n";

cin>>left1;

cout<<"Bottom Left: "<<"\n";

cin>>left2;

cout<<"Top Right: "<<"\n";

cin>>right1;

cout<<"Bottom Right: "<<"\n";

cin>>right2;

// For rectangle 2

int left3, left4, right3, right4;

cout<<"Enter Second rectangle coordinates: "<<"\n";

cout<<"Top Left: "<<"\n";

cin>>left3;

cout<<"Bottom Left: "<<"\n";

cin>>left4;

cout<<"Top Right: "<<"\n";

cin>>right3;

cout<<"Bottom Right: "<<"\n";

cin>>right4;

Axis l1 = {left1, left2}, r1 = {right1, right2};

Axis l2 = {left3, left4}, r2 = {right3, right4};

if (checkRect(l1, r1, l2, r2)) {

cout<<"The Rectangles Overlap"; }

else {

cout<<"Rectangles Don't Overlap";}

// Print Rectangle 1

rectangle (left1, right1, left2, right2);

// Print Rectangle 2

rectangle (left3, right3, left4, right4);

return 0;

}

5 0
3 years ago
Suppose you can access the caches in the local DNS servers of your department. Can you propose a way to roughly determine the We
lubasha [3.4K]

Answer:

We can periodically take a snapshot of the Domain Name System (DNS) caches in the local  Domain Name System (DNS) servers.

Explanation:

We can periodically take a snapshot of the Domain Name System (DNS) caches in the local  Domain Name System (DNS) servers. The Web server that appears most frequently in the  Domain Name System (DNS) caches is the most popular server. This is because if more users are interested in a Web server, then Domain Name System (DNS) requests for that server are more frequently sent by users. Thus, that Web server will appear in the  Domain Name System (DNS) caches more frequently.  

6 0
3 years ago
How many people in the world
sveticcg [70]

Answer:

Around seven billion people

4 0
2 years ago
Which of the following sets of data would be presented best in a histogram.
anastassius [24]
I do not believe you answer is right. I believe it would be B the average montly sales for the big toy company. Only documenting the last month is not enough information to make a histogram, and a histogram asks for information based on one subject not multiple subjects. Asking for the number of each type of candy sold last month would make a normal graph comparing the difference in how much each candy sold, so your answer should be B.
3 0
3 years ago
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