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2 years ago

Two thirds the sum of 30 and a number is 26 write this statement out as an equation and solve

Mathematics

1 answer:

zloy xaker [14]2 years ago

7 0

Answer:s

Step-by-step explanation:

Let the number be x

2/3(30+x) = 26

2(30+x) = 26(3)

60 + 2x = 78

2x = 78 - 60

2x = 18

x = 18/2

x = 9

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Solve equation, check for extraneous solutions

fiasKO [112]

Start with

$1=\dfrac{1}{n^2}+\dfrac{n^2-4n-5}{3n^2}$

We observe that both fractions are not defined if $n=0$ . So, we will assume $n \neq 0$ .

We multiply both numerator and denominator of the first fraction by 3 and we sum the two fractions:

$1=\dfrac{3}{3n^2}+\dfrac{n^2-4n-5}{3n^2} = \dfrac{n^2-4n-2}{3n^2}$

We multiply both sides by $3n^2$ :

$n^2-4n-2=3n^2$

We move everything to one side and solve the quadratic equation:

$2n^2+4n+2=0 \iff 2(n^2+2n+1)=0 \iff 2(n+1)^2=0 \iff n+1=0 \iff n=-1$

We check the solution:

$1=\dfrac{1}{1}+\dfrac{1+4-5}{3} \iff 1 = 1+0$

which is true

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3 years ago

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jasenka [17]

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3 years ago

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3. The formula to find the surface area of a sphere is to take the radius of the sphere and square it and multiply that amount b

KatRina [158]

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3 years ago

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If a spring is oscillating (moving) according to the velocity equation v(t) = 2sin(t) (in ft/s), then what is its displacement o

Feliz [49]

ANSWER

4 ft

EXPLANATION

The velocity equation of the oscillating spring is given by the function.

$v(t)=2 \sin(t) \: \: {ms}^{ - 1}$

To find the displacement function, we need to to Integrate the velocity function.

$s(t) = \int \: 2 \sin(t) dt$

$s(t) = - 2 \cos(t) + k$

At time t=0, there was no displacement.

This implies that,

$s(0) = 0$

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The displacement function then becomes,

$s(t) = - 2 \cos(t) + 2$

To find the displacement over the first π seconds, we put

$t = \pi$

into the equation for the displacement to get,

$s(\pi) = - 2 \cos(\pi) + 2$

$s(\pi) = - 2 ( - 1) + 2$

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3 years ago

The sphere and cylinder have the same radius and height.

AlexFokin [52]

Answer:A 12 m3

Step-by-step explanation:

100% correct

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2 years ago

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