
Let's check if (3 , 6) is the point of intersection of the given lines ~

and

If the point is the point of intersection of these two lines, then it should satisfy both the equations ~
let's try each of them, using x coordinate of point.



So, the point didn't actually satisfy one of the equation. hence we can infer that the given statement is wrong.
First, we group together the terms with variables in one side by subtracting 3/2 x and 5 from both sides of the equation.
(2/3)x - (3/2)x + 5 - 5 = (3/2)x - (3/2)x - 5
(-5/6)x = -5
The value of x from the equation is 6.
Not always but your answer is sometimes
The equation that can not be represented is B because the variables are mixed up and are not matching with the correct formula.
4a^5b^8 I hope this helps