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Anni [7]
3 years ago
15

Kali builds a tower using only red, green, and blue toy bricks in a ratio of 4:3:1. She then removes 1/2 of the green bricks and

adds 1/3 more blue bricks, reducing the size of the tower by 14 bricks. How many red bricks will she need to add in order to double the total number of bricks used to build the original tower?
A. 82
B. 96
C. 110
D. 120
E. 192
Mathematics
1 answer:
Neko [114]3 years ago
4 0

Answer:

110 red bricks she add in order to double the total number of bricks

Step-by-step explanation:

Kali builds a tower using only red, green, and blue toy bricks in a ratio of 4:3:1.

The original ratio of red, green and blue is 4x, 3x and x

the total of the original is 4x+3x+x=8x

She then removes 1/2 of the green bricks

she remove \frac{3}{2}x

adds 1/3 more blue bricks

x+\frac{1}{3}x=\frac{4}{3}x

The total of new is 4x+\frac{3}{2}x+\frac{4}{3}x=\frac{41}{6}x

size is reduced by 14 bricks

total of original - total of new = 14

8x -\frac{41}{6}x=14

\frac{7}{6}x=14

multiply both sides by 6/7

x= 12

original number of bricks = 8x = 8 times 12= 96

total of new bricks =  \frac{41}{6}(12)=82

Double the original number = 2 \cdot 96 = 192

the number of red bricks needs to add is

192-82=110

110 red bricks she add in order to double the total number of bricks

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Got it right on edge 100%

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2 years ago
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What is the value of the sum of all the terms of the geometric series 300, 60, 12, …?
ruslelena [56]
<h3>Answer:   375</h3>

=========================================

Work Shown:

a = 300 = first term

r = 60/300 = 0.2 = common ratio

We multiply each term by 0.2, aka 1/5, to get the next term.

Since -1 < r < 1 is true, we can use the infinite geometric sum formula below

S = a/(1-r)

S = 300/(1-0.2)

S = 300/0.8

S = 375

----------

As a sort of "check", we can add up partial sums like so

  • 300+60 = 360
  • 300+60+12 = 360+12 = 372
  • 300+60+12+2.4 = 372+2.4 = 374.4
  • 300+60+12+2.4+0.48 = 374.4+0.48 = 374.88

and so on. The idea is that each time we add on a new term, we should be getting closer and closer to 375. I put "check" in quotation marks because it's probably not the rigorous of checks possible. But it may give a good idea of what's going on.

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Side note: If the common ratio r was either r < -1 or r > 1, then the terms we add on would get larger and larger. This would mean we don't approach a single finite value with the infinite sum.

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2 years ago
Vector V is in standard position and makes an angle of 50° with the positive x-axis. Its magnitude is 18. Write V in component f
Umnica [9.8K]

Answer:

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11.57i + 13.79j

Step-by-step explanation:

V = 18 units at an angle of 50° to the positive x-axis

In component Form, this is how each component is calculated

a = 18cos50° = 11.57 units east

b = 18sin50° = 13.79 units upwards

check if your answer is correct

\sqrt{11.57^{2} +13.79^{2} } = 18.0

In vector component form ai + bj = 11.57i + 13.79j

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