If the rectangle perimeter equals 42 meters what is the length?

On Sunday, Sheldon bought 4 1/2 kg of plant food. He used 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plant

VladimirAG [237]

Answer:

a) $2\frac{7}{12}$ kg of plant food did Sheldon have left.

b) She need is $\frac{43}{12}$ kg and she don't have enough to left.

Step-by-step explanation:

Given : On Sunday, Sheldon bought $4\frac{1}{2}$ kg of plant food. He used $1\frac{2}{3}$ kg on his strawberry plants and used $\frac{1}{4}$ kg for his tomato plants.

To find :

a) How many kilograms of plant food did Sheldon have left? Write one or more equations to show how you reached your answer.

Solution :

Sheldon bought plant food $4\frac{1}{2}=\frac{9}{2}$ kg.

He used strawberry plants $1\frac{2}{3}=\frac{5}{3}$ kg.

He used tomato plants $\frac{1}{4}$ kg

Kilograms of plant food did Sheldon have left is given by,

$L=\frac{9}{2}-(\frac{5}{3}+\frac{1}{4})$

$L=\frac{9}{2}-\frac{23}{12}$

$L=\frac{54-23}{12}$

$L=\frac{31}{12}$

$L=2\frac{7}{12}$

Therefore, $2\frac{7}{12}$ kg of plant food did Sheldon have left.

b) Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will he need? Does he have enough left to do so?

Solution :

Sheldon wants to feed his strawberry plants 2 more times.

i.e. Strawberry plants used is $2(\frac{5}{3})=\frac{10}{3}$ kg.

His tomato plants one more time i.e. $\frac{1}{4}$ kg.

Total plant she need is $\frac{10}{3}+\frac{1}{4}=\frac{43}{12}$

As $\frac{31}{12}$

No she don't have enough to left.

4 0

3 years ago

Use mathematical induction to prove that if L is a linear transformation from V to W, then L (α1v1 + α2v2 +· · ·+αnvn)= α1L (v1)

e-lub [12.9K]

Answer:

The proof is shown in the explanation below.

Step-by-step explanation:

Analysis:

The proof by induction focuses on n. In this case, let n = 1, and $L^{1}$ will be a linear operator since $L^{1} = L$

The exercise will show that $L^{n}$ is a linear operator on V and that $L^{n+1}$ is also a linear operator on V. This, follows that:

$L^{n+1} (av) = L(L^{m}(v_{1}+v_{2})\\ = L(L^{m} (v_{1} + L^{m}v_{2})\\ = L(L^{m}v_{1} + L(L^{m}v_{2})\\ = L^{m+1}(v_{1}) + L^{m+1}(v_{2})$

6 0

3 years ago

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At a pizza shop, you can choose thick or thin crust, red or white sauce, and toppings of pepperoni, cheese, and onion. How many

lozanna [386]

Answer:

72

Step-by-step explanation:

8 0

3 years ago

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I rlly need a worded story thingy that equals 2361.

Flura [38]

I’m not sure what the question is? But if you’re referring to Jack then here you go: if Jack had 3 apples and now he ate 2 he would end up with 1 apple left.

5 0

3 years ago

Solve the equation for x. the square root of the quantity x plus 4 end quantity minus 7 equals 1

HACTEHA [7]

Answer:

Step-by-step explanation:

I hope it helps :)

$\sqrt{x+4} -7=1\\\mathrm{Add\:}7\mathrm{\:to\:both\:sides}\\\sqrt{x+4}-7+7=1+7\\\sqrt{x+4}=8\\\mathrm{Square\:both\:sides}\\\left(\sqrt{x+4}\right)^2=8^2\\x+4=64\\x = 64-4\\x = 60$

3 0

3 years ago