Simplify the expression 8x^2y^2/10 x^2y^3 and the missing terms. The simplest form of 8x^2y^2/10x^2y^3 has in the numerator and
1 answer:
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The space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.
<h3>What is a cone?</h3>It is defined as the three-dimensional shape in which the base is a circular shape and if we go from circular base to top the diameter of the circle reduces and at the vertex, it becomes almost zero.
We know the volume of the cylinder is given:
r = 10/2 = 5 FT
h = 12 FT
V = 300π cubic FT
Volume of the cone:
v = 100π cubic FT
Space is inside the cylinder but outside the cone = 300π - 100π
= 200π cubic FT
= 628.32 cubic FT
Thus, the space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.
Learn more about the cone here:
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Answer:
Yes, since the test statistic value is greater than the critical value.
Step-by-step explanation:
Data given and notation
represent the mean for the downtown restaurant
represent the mean for the freeway restaurant
represent the sample standard deviation for downtown
represent the sample standard deviation for the freeway
sample size for the downtown restaurant
sample size for the freeway restaurant
t would represent the statistic (variable of interest)
significance level provided
Develop the null and alternative hypotheses for this study?
We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:
(1)
t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.
Determine the critical value.
Based on the significance level and
we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.
For this case the value is
Calculate the value of the test statistic for this hypothesis testing.
Since we have all the values we can replace in formula (1) like this:
What is the p-value for this hypothesis test?
Since is a right tailed test the p value would be:
Based on the p-value, what is your conclusion?
Comparing the p value with the significance level given we see that
so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.
The best option would be:
Yes, since the test statistic value is greater than the critical value.
Answer:
Forth term = x + 6
Fifth term = x + 8
Sixth term = x + 10
Formular for nth term: