Answer:
H0: μ = 5 versus Ha: μ < 5.
Step-by-step explanation:
Given:
μ = true average radioactivity level(picocuries per liter)
5 pCi/L = dividing line between safe and unsafe water
The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.
A type I error, is an error where the null hypothesis, H0 is rejected when it is true.
We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.
Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.
Answer:
Angle BAF and angle BAC is incorrect.
They overlap: adjacent angles do not overlap.
Answer: Total Volume = 15π + 18 π= 33π cubic mm
Step-by-step explanation:
What is the volume of the composite figure? Leave the answer in terms of π.
_33π mm3
We have a cone here conjoined to a semi-sphere.
so
Cone volume: C = (1/3)*(πr^2) * h
semi-sphere volume : V = (1/2)* (4/3) * (π * r^3)
r = 3 mm and h = 5mm
so C = (1/3)*(π (3)^2) * 5 = 15π cubic mm
V = (1/2)* (4/3) * (π * 3^3) = 18 π cubic mm
Total Volume = 15π + 18 π= 33π cubic mm
Well, first you have to convert to one unit... then simplify
D:H
150m:16500cm
150m:160m
150:160
30:33
10:11
