Answer:
<h2>15m/s</h2>
Explanation:
Step one:
given data
acceleration a=4m/s^2
final velocity v=35m/s
time t=5 seconds
Step two:
Required
initial velocity u=?
Applying the first equation of motion
v=u+at
substituting we have
35=u+4*5
35=u+20
u=35-20
u=15 m/s
The initial velocity is 15m/s
Yes because it would take the dog twenty five with (0.8 miles per minute) minutes to reach the cat at basking and it would take the cat 25 minutes (0.6 miles per minute) to reach the fence the reason they take the same amount of time to reach despite the dog having more distance to cover is because the dog could go faster then the cat.
for any ray on the mirror, incident angle - reflected angle.
angles wrt a normal to mirror
M = 1.9 g = 1.9 x 10⁻³ kg, the mass of the spider
f = 1.2 Hz, the fundamental frequency
The circular frequency is
ω = 2πf = 2.4π cycles/s
For oscillatory motion,
ω² = k/m
where k = the spring constant.
Therefore
k/m = (2.4π)²
k = (1.9 x 10⁻³ kg)*(2.4π 1/s)² = 0.108 N/m
Answer: 0.108 N/m
Answer:
n=2,3
Explanation:
We have to take into account the expression for the fundmentals modes in a vibrating cord
in this case we have resonant at 880Hz and 1320Hz
Hope this helps!!