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3 years ago

What is quantum entanglement is a simple explanation?

2 answers:

4 0

Quantum entanglement is a physical phenomenon that occurs when pairs or groups of particles are generated or interact in ways such that the quantum state of each particle cannot be described independently — instead, a quantum state must be described for the system as a whole.

klio [65]3 years ago

4 0

electrons one bonded together, still just as connected even when separated.

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Explain what happens to an atom when protons are added or removed from its nucleus

dsp73

Neutrons do not carry an electrical charge so adding or removing them from the nucleus does not change the electrical charge of the nucleus. ... So, adding or removing protons from the nucleus changes what element that atom is! For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium.

4 0

4 years ago

The setting sun is actually visible after it has dropped below the horizon due to the bending of light waves entering the atmosp

Yuki888 [10]

That's one result of "refraction".

4 0

3 years ago

Read 2 more answers

A power plant generates 150 MW of electrical power. It uses a supply of 1000 MW from a geothermal source and rejects energy to t

marissa [1.9K]

Answer:

- the power to the air is 850 MW

- mass flow rate of the air is 84577.11 kg/s

Explanation:

Given the data in the question;

Net power generated; $W_{net$ = 150 MW

Heat input; $Q_k$ = 1000 MW

Power to air = ?

For closed cycles

Power to air Q₀ = Heat input; $Q_k$ - Net power generated; $W_{net$

we substitute

Power to air Q₀ = 1000 - 150

Q₀ = 850 MW

Therefore, the power to the air is 850 MW

given that ΔT = 10 °C

mass flow rate of air required will be;

⇒ Q₀ / CpΔT

we know that specific heat of air at p=c ; Cp = 1.005 kJ/kg.K

we substitute

⇒ ( 850 × 10³ ) / [ 1.005 × 10 ]

⇒ ( 850 × 10³ ) / 10.05

⇒ 84577.11 kg/s

Therefore, mass flow rate of the air is 84577.11 kg/s

3 0

3 years ago

An automobile with a mass of 1240.00 kg has 3.99 m between

Vitek1552 [10]

Answer:

$948.15248\ N$

$5134.04751\ N$

Explanation:

$F_f$ = Force on front wheels

$F_r$ = Force on rear wheels

Distance between CG and rear wheel = 3.99-0.622 = 3.368 m

$F_r=1240\times 9.81-F_f$

As the forces are conserved we have

$(1240\times 9.81-F_f)3.368=F_f\times 0.622\\\Rightarrow 12164.4-F_f=\dfrac{0.622F_f}{3.368}\\\Rightarrow 12164.4-F_f=0.18467F_f\\\Rightarrow F_f=\dfrac{12164.4}{1.18467}\\\Rightarrow F_f=10268.09503\ N$

On rear wheels

$F_r=1240\times 9.81-10268.09503\\\Rightarrow F_r=1896.30497\ N$

The force on each rear whees is $\dfrac{1896.30497}{2}=948.15248\ N$

Force on each front wheel is $\dfrac{10268.09503}{2}=5134.04751\ N$

8 0

3 years ago

A steam engine absorbs 1.98 × 105 j and expels 1.49 × 105 j in each cycle. assume that all of the remaining energy is used to do

VikaD [51]

B) The heat absorbed by the engine is $Q_{in} = 1.98 \cdot 10^5 J$ while the heat expelled is $Q_{out} = 1.49 \cdot 10^5 J$ , therefore the work done by the engine is the difference between the heat absorbed and the heat expelled:
$W=Q_{in} - Q_{out} = 1.98 \cdot 10^5 J - 1.49 \cdot 10^5 J = 0.49 \cdot 10^5 J$

a) The efficiency of the engine is the ratio between the work done by the engine and the heat absorbed, therefore:
$\eta= \frac{W}{Q_{in}} = \frac{0.49 \cdot 10^5 J}{1.98 \cdot 10^5 J}=0.247 = 24.7\%$

8 0

4 years ago