Answer:
B.The mean weight of dogs at Lawrenceville’s Veterinarian Office is about 72 pounds and the mean weight of dogs at Snellville’s Veterinarian Office is about 73 pounds.
Step-by-step explanation:
Lawrenceville’s Veterinarian Office distribution is almost symmetrical so the mean is almost the same as the median
Snellville’s Veterinarian Office distribution is left skewed so mean is less than the median, mean is less than 76
Answer:
2.1
Step-by-step explanation:
let unknown number be x
3/4x + 3.5= 6.5 - 2/3x
collect like terms
3/4x+2/3x=6.5 - 3.5
17/12x = 3
cross multiply
12 * 3=17x
36=17x
x=36/17
x=2.1
Answer:
a) 336
b) 593775
c) 83160
d) P=0.14
e) P=0.0019
Step-by-step explanation:
We have wine supply includes 8 bottles of zinfandel, 10 of merlot, and 12 of cabernet.
a) If he wants to serve 3 bottles of zinfandel and serving order is important. We get:
C=8·7·6=336
b) {30}_C_{6}=\frac{30!}{6!(30-6)!}
{30}_C_{6}=593775
c) {8}_C_{2} · {10}_C_{2} · {12}_C_{2}=
=\frac{8!}{2!(8-2)!} · \frac{10!}{2!(10-2)!} · \frac{12!}{2!(12-2)!}
=28 · 45 · 66
=83160
d) We calculate the number of possible combinations:
{30}_C_{6}=593775
We calculate the number of favorable combinations:
{8}_C_{2} · {10}_C_{2} · {12}_C_{2}=83160
The probability that this results in two bottles of each variety being is
P=83160/593775
P=0.14
e) We calculate the number of possible combinations:
{30}_C_{6}=593775
We calculate the number of favorable combinations:
{8}_C_{6} + {10}_C_{6} + {12}_C_{6}= 28+210+924=1162
The probability is
P=1162/593775
P=0.0019
Answer:
(-5-5x)/(4x+3
Step-by-step explanation:
Replace x with y to get (-3y-5)/(4y+5). Solve for y to get (-5-5x)/(4x+3).