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nekit [7.7K]
3 years ago
11

The number of seats in a row has been increased at a rectangular-shape movie theater after renovation so that it is now five mor

e than the total number of rows. How many rows are in in the theater, if its total seating capacity is 126 people now?
Mathematics
1 answer:
Damm [24]3 years ago
4 0

Let the number of rows be = r

Let the number of seats per row be = s

we know that the number of seats is 126.

So, s\times r=126    ..... (1)

As given, there are five more seats per row than the number of rows, so we can say that:

s=r+5

Putting this in equation (1)

(r+5)*r=126

r^{2}+5r=126

r^{2}+5r-126=0

r^{2}+14r-9r-126=0

(r+14)(r-9)=0

r=-14 and r=9 (neglecting the negative value) we get r=9

And s=r+5

so, s =9+5=14

Hence, there are 5 rows and 14 seats per row.

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Answer:

  \textbf{C}\quad\dfrac{13}{20}=\dfrac{25}{40} \qquad\textbf{FALSE}

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Each of the equations represents equivalent fractions except the one in choice C.

  13/20 = 26/40, not 25/40.

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<em>Comment on equal sign</em>

IMO, one should never use an equal sign where things are not equal--unless there is a clear indication you understand they are not equal. The equal sign should be regarded as a sacred symbol, with very specific rules as to its meaning and use.

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AC=CE and D is the midpoint of CE. If CE = 10x+18 DE = 7x-1 and BC = 9x-3 find AB
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We know the CE = 10x + 18 and DE = 7x - 1 and D is the midpoint of CE

⇒ CE = 2 * DE

⇒ 10x + 18 = 2 * (7x - 1)

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⇒ -4x = -20

⇒ x = 5

Now we also know that BC = 9x - 3 and AC = CE = 10x + 18

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