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3 years ago

For this exercise, you'll use the Rectangle class below (you can assume that the length and width are measured in feet).

Computers and Technology

1 answer:

dusya [7]3 years ago

8 0

Answer:

The solution code is written in Python:

class Carpet:
def __init__(self, rect, cost):
self.size = rect
self.costPerSqFoot = cost
def cost(self):
carpetCost = self.size.area() * self.costPerSqFoot
return carpetCost

Explanation:

Presume that there is existence of Rectangle class as given in the question, Carpet class is written. The Carpet constructor is defined that take Rectangle object, rect, and cost as parameter (Line 2). To create data member of Carpet class, keyword "self" is used to precede with the name of the data members, size and costPerSqFoot (Line 3-4). The data members are initialized with the parameter rect and cost, respectively.

Next, cost method is defined (Line6 - 8). Within the cost method, the area method of Rectangle object is invoked by expression, self.size.area() and this will return the area value and multiplied with the costPerSqFoot to get the carpet cost and return it as output (Line 8).

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3 years ago

Which of the following can you do after switching to Outline view? Select all the options that apply.

Lina20 [59]

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a. Change the level of text.

c. Move text within a slide.

d. View an outline of the presentation.

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1. Change the level of text.

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3. View an outline of the presentation.

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3 years ago

Consider the following program written in C syntax:

postnew [5]

The values of the variables value and list after each of the three calls to

swap are:

value = 2 and list[5] = {1, 3, 5, 7, 9};
value = 2 and list[5] = {3, 1, 5, 7, 9};
value = 2 and list[5] = {3, 1, 5, 7, 9};

<h3>How to determine the values of variable value and the list?</h3>

1. Passed by value

In this case, the values of the actual arguments remain unchanged; So the variable value and the list would retain their initial values

The end result is:

value = 2 and list[5] = {1, 3, 5, 7, 9};

2. Passed by reference

With pass by reference, the arguments are changed.

Given that

value = 2 and list[5] = {1, 3, 5, 7, 9};

The value of variable value is swapped with list[0].

So, we have:

value = 1 and list[5] = {2, 3, 5, 7, 9};

Then list[0] and list[1] are swapped

So, we have:

value = 1 and list[5] = {3, 2, 5, 7, 9};

Lastly, value and list[value] are swapped

So, we have:

value = 2 and list[5] = {3, 1, 5, 7, 9};

The end result is:

value = 2 and list[5] = {3, 1, 5, 7, 9};

3. Passed by value-result

Since there is no loop in the program, the pass by value-result has the same output as the pass by reference.

So, the end result is:

value = 2 and list[5] = {3, 1, 5, 7, 9};