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bazaltina [42]
3 years ago
7

Chức năng của hàm MOD(number, divisor)?

Computers and Technology
1 answer:
Kryger [21]3 years ago
8 0

Answer:

MOD -> modulo, là phần dư, vì vậy hàm / phương thức MOD () xuất ra thương của số bằng số chia.

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The Java compiler does not check for an ArrayIndexOutorBoundsException during the compilation of a program containing arrays. O
yulyashka [42]

Answer:

TRUE

Explanation:

  • Let us first understand what is an ArrayIndexOutOfBounds Exception.
  • As the name itself suggests the index for the array has gone out of bound (permissible value) and an exception (anamoly) is resulted.
  • So, it throws an error.
  • That means if an array, Employee of size n is defined then the permissible elements are Employee[0] to Employee[n-1]. If any negative index or with the index is greater than n-1 is tried to access it throws an error saying ArrayIndexOutOfBounds Exception.
  • In java, during the compilation of the program the compiler doesn't check for the ArrayIndexOutOfBounds Exception.It checks during running the program.
  • So, it is called a Runtime Exception.
7 0
3 years ago
Which of the following is the best example of an installation issue
Tasya [4]

Answer:

A user made an error while trying to set up a software program.

6 0
3 years ago
Read 2 more answers
Consider a system consisting of m resources of the same type, being shared by n processes. Resources can be requested and releas
Mama L [17]

Answer:

Explanation:

The system will be deadlock free if the below two conditions holds :

Proof below:

Suppose N = Summation of all Need(i), A = Addition of all Allocation(i), M = Addition of all Max(i). Use contradiction to prove.

Suppose this system isn't deadlock free. If a deadlock state exists, then A = m due to the fact that there's only one kind of resource and resources can be requested and released only one at a time.

Condition B, N + A equals M < m + n. Equals N + m < m + n. And we get N < n. It means that at least one process i that Need(i) = 0.

Condition A, Pi can let out at least 1 resource. So there will be n-1 processes sharing m resources now, Condition a and b still hold. In respect to the argument, No process will wait forever or permanently, so there's no deadlock.

5 0
3 years ago
Differentiate between programming and coding
r-ruslan [8.4K]
Coding means creating codes from one language to another. Programming means to program a machine to perform using a set of instructions.
7 0
3 years ago
10. In step 4 of the CSMA/CA protocol, a station that successfully transmits a frame begins the CSMA/CA protocol for a second fr
Neporo4naja [7]

Answer:

It is done to avoid collision among the channel.

Explanation:

CSMA/CD stands for carrier sense multiple access/collision detection.

It is a media access protocol that tells the devices how to respond when a channel is used simultaneously by two devices. The main purpose is to manage the transmission when a collision is encountered.

In the given scenario when the channel is detected idle, the station does not transmits second frame in order to avoid collision. CSMA/CD protocol is designed so that after transmission of first frame, second frame transmission is started at step 2 instead of step 1.

Following is given the flow chart that depicts the working of the protocol CSMA/CD:

<h2> I hope it will help you!</h2><h2 /><h2 />

7 0
3 years ago
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