Solve for x: -1 < x + 3 < 5

Mathematics

1 answer:

Oxana [17]3 years ago

7 0

<h3>Answer: Choice B) -4 < x < 2</h3>

Work Shown:

-1 < x+3 < 5

-1-3 < x+3-3 < 5-3 ... subtract 3 from all sides

-4 < x < 2

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3 years ago

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bulgar [2K]

<u>Given</u>:

The given equation is $x^{2} -3x-7=0$

We need to determine the exact solutions of the equation.

<u>Exact solution:</u>

The exact solution of the equation can be determined by solving the equation using quadratic formula,

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3 years ago

(X-4) (x+2)=16 <br> What’s the standard form

Reika [66]

Step-by-step explanation:

$(x - 4)(x + 2) = 16 \\ {x}^{2} + (- 4 + 2)x + ( - 4) \times 2= 16 \\ {x}^{2} - 2x - 8 - 16 = 0 \\ {x}^{2} - 2x - 24 = 0 \\ is \: the \: standard \: form.$