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schepotkina [342]

3 years ago

10

"Can anyone help me?

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1 answer:

Cloud [144]3 years ago

4 0

i cant read it clearly

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A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 meter per second, while the cat

LenKa [72]

Answer:

They'll meet after 200 meters , if they simultaneously start running towards each other.

Step-by-step explanation:

Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.

Dog: Distance =Speed x time: x=30t

Cat: Distance = 200-x

=24t

The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs

So they will meet after 3.7 seconds

To check:

Distance travelled by dog :x=30(3.7)

=111.11 meters

Distance travelled by cat: 24t=24(3.7)

=88.89 meters

Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89

=200 meters

6 0

2 years ago

X-2y=8<br> 4x+y=5<br> Solve linear systems by Multiplying

Lisa [10]

<h2> x = 2 and y = - 3</h2>

Step-by-step explanation:

The given system of linear equations:

x - 2y = 8 ........ (1)

and 4x + y = 5 ........ (2)

To find, the values of x and y = ?

Multiplying equation (2) by 2, we get

2(4x + y) = 5 × 2

⇒ 8x + 2y = 10 ........ (3)

Adding equations (1) and (3), we get

x - 2y + (8x + 2y) = 8 + 10

⇒ x - 2y + 8x + 2y = 8 + 10

⇒ 9x = 18

⇒ x = 2

Put x = 2 in (1), we get

2 - 2y = 8

⇒ 2y =2 - 8

⇒ 2y = - 6

⇒ y = - 3

∴ x = 2 and y = - 3

4 0

3 years ago

Mr. Williams is building a sand box for his children. It costs $228 for the sand if he builds a rectangular-sand box with dimens

Andru [333]

Answer: The correct option is (C) $342.

Step-by-step explanation: Given that Mr. Williams is building a sand box for his children and is costs $228 for the sand if he builds a rectangular-sand box with dimensions 9 ft by 6 ft.

We are to find the cost of the sand if he decides to increase the size to $13\frac{1}{2}~\textup{ft by }9~\textup{ft}.$

Since the box is empty from inside, so we will be considering the perimeter of the box, not area.

The perimeter of the rectangular-sand box with dimensions 9 ft by 6 ft is

$P_1=2(9+6)=30~\textup{ft},$

and the perimeter of the rectangular-sand box with dimensions $13\frac{1}{2}~\textup{ft by }9~\textup{ft}.$ is

$P_2=2\left(13\dfrac{1}{2}\times9\right)=2(13.5\times9)=45~\textup{ft}.$

Now, we will be using the UNITARY method.

Cost of sand for building rectangular-sand box with perimeter 30ft = $228.

So, cost of sand for building rectangular-sand box with perimeter 1 ft will be

$\$\dfrac{228}{30}.$

Therefore, the cost of sand for building rectangular-sand box with perimeter 45 ft is given by

$\$\dfrac{228}{30}\times45=\$342.$

Thus, the required cost of the sand is $342.

Option (C) is CORRECT.

3 0

3 years ago

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In circle A shown below, the measure of ∠BAD is 148°:

Bond [772]

43 i alredy learned that in school

3 0

3 years ago

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A parabola has a minimum value of 0, a y-intercept of 4, and an axis of symmetry at x = -2.

Nitella [24]

The answer is d. The y-intercept is at 4, the parabola is at 0 and the axis of symmetry is x=-2.

5 0

3 years ago

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