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kvv77 [185]
3 years ago
14

Someone please help me! 64x squared y cubed + 8xy divided by 4xy squared

Mathematics
1 answer:
Burka [1]3 years ago
7 0
64x^2+8xy/4xy^2. This should be what you’re looking for hopefully
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How to prove this using trig identities?
Pavlova-9 [17]

Step-by-step explanation:

tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)

 

                      = (sin2B + cos2B)/[(cosB)(sinB)]

 

                       = 1/[(cosB)(sinB)]

 

                        = (1/cosB)(1/sinB)

 

                        = (secB)(cscB)

7 0
3 years ago
The picture below shows a pole and its shadow:
Angelina_Jolie [31]

The answer is 112 centimeters.

As this problem represents a right triangle, here we need to apply the Pythagorean Theorem.

  • h = √113² - 15²
  • h = √12769 - 225
  • h = √12544
  • h = 112 centimeters

8 0
2 years ago
6. Which formula is 8 less than twice a number? q=2w-8​
hammer [34]

Answer:

Yes that is correct

7 0
3 years ago
Whats the answer to 12.9 – 3.1) × 6.2 – 2 + 43
suter [353]

Answer:

101.76

Step-by-step explanation:

(12.9−3.1)(6.2)−2+43

=(9.8)(6.2)−2+43

=60.76−2+43

=58.76+43

=101.76

3 0
2 years ago
Read 2 more answers
A Ferris wheel has a radius of 10 m, and the bottom of the wheel passes 1 m above the ground. If the Ferris wheel makes one comp
Morgarella [4.7K]

Answer:

y = 11 - 10cos(0.1\pi t)

Step-by-step explanation:

Suppose at t = 0 the person is 1m above the ground and going up

Knowing that the wheel completes 1 revolution every 20s and 1 revolution = 2π rad in angle, we can calculate the angular speed

2π / 20 = 0.1π rad/s

The height above ground would be the sum of the vertical distance from the ground to the bottom of the wheel and the vertical distance from the bottom of the wheel to the person, which is the wheel radius subtracted by the vertical distance of the person to the center of the wheel.

y = h_g + d_b = h_g + R - d_c (1)

where h_g = 1 is vertical distance from the ground to the bottom of the wheel, d_b is the vertical distance from the bottom of the wheel to the person, R = 10 is the wheel radius, d_c is the vertical distance of the person to the center of the wheel.

So solve for d_c in term of t, we just need to find the cosine of angle θ it has swept after time t and multiply it with R

d_c = Rcos(\theta(t)) = Rcos(\omega t) = 10cos(0.1\pi t)

Note that d_c is negative when angle θ gets between π/2 (90 degrees) and 3π/2 (270 degrees) but that is expected since it would mean adding the vertical distance to the wheel radius.

Therefore, if we plug this into equation (1) then

y = h_g + R - d_c = 1 + 10 - 10cos(0.1\pi t) = 11 - 10cos(0.1\pi t)

7 0
3 years ago
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