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Inga [223]
2 years ago
8

Name a pair of opposite rays

Mathematics
1 answer:
Elis [28]2 years ago
3 0
AB and BC.

Also, it is EXTREMELY important that you put an arrow facing to the left above AB and an arrow facing to the right above BC.
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(15/8+2/5)+(-7/8) show ur work
stepan [7]
The answer is 7/5 th. You can add fractions without first having a common denominator so you would change the 8's by multiplying it by 5 to get 40 and you would multiply the 5 by 8 to get 40 as well. And the rule whatever you do to the bottom you have to do to the top so whatever you multiplied 8 by do the same for the numerator and whatever you multiplied 5 by you do the same for the numerator. So your new equation would be (75/40+16/40)+(-35/40). you would then add the numerator's across to get 56 and the denominator would stay the same so the answer is 56/40. But you have to now simplify 56/40 down to 14/10 and then once more to 7/5 which is the final answer.
6 0
3 years ago
Marcus painted 1/3 of his bedroom in 4/5 of an hour. at this rate how long will it take him to paint his entire room
Leno4ka [110]
It will take him 2 2/5 hours
8 0
3 years ago
-4(7a+5) = -160 Show All Work!
Fynjy0 [20]

Answer:

a=-20

Step-by-step explanation:

-4(7a+5)=-160

7a+(-20)=-160 Multiply -4 and 5

7a=-140 Subtract -20 from -160

a=-20 Divide 7 by -140

7 0
3 years ago
Which fraction expresses 36/80 in lowest terms? A. 9/20 B. 18/40 C.4/5 D. 18/20
jenyasd209 [6]
To solve this problem, we need to factor 36 and 80, then find greatest common factor, and divide numerator and denominator by this greatest common factor.
36/80 = (4*9)/(4*20)= 9/20

Answer A. 9/20.

6 0
3 years ago
What central tendency means to find the number that occurs most often?
Ghella [55]

Answer:The mean is the most frequently used measure of central tendency because it uses all values in the data set to give you an average. For data from skewed distributions, the median is better than the mean because it isn't influenced by extremely large values.

Step-by-step explanation:

3 0
2 years ago
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