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Softa [21]
3 years ago
9

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Mathematics
1 answer:
Lelu [443]3 years ago
7 0

Answer:

B?

Step-by-step explanation:

my best guess! it is the best!

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Three years back , a father was 24 years older than his son .at present,the father is five times as old as the son.how old will
azamat

Answer:

The son is 5 I think

Step-by-step explanation:

24+3=27

27 divided by 5 = 5.4

round 5.4 to 5 since it is under .5

and you get 5

3 0
3 years ago
Gia opened two savings accounts at two diffrent banks. One account earns an annual 3.4% simple interest, and the other earns hal
dsp73

Interest from first account is :

I_1 = \dfrac{p\times r \times t}{100}\\\\I_1 = \dfrac{509\times 3.4\times 3}{100}\\\\I_1 =\$ 51.918

Interest form second account is :

I_2 = \dfrac{p\times r\times t}{100}\\\\I_2 = \dfrac{509\times 1.7\times 3}{100}\\\\I_2 =  \$25.959

So, total interest is :

I = I_1 + I_2 \\\\I = 51.918 + 25.959\\\\I = \$77.877

Therefore, total interest is $77.877 .

5 0
3 years ago
Please ASAP i need help
NeX [460]

Answer:

Bar chart

Step-by-step explanation:

easier to understand

6 0
3 years ago
PLEASE HELP FAST...The dot plots show the numbers of children’s books purchased by customers at two different bookstores on one
Katena32 [7]

Answer:

The mode of the data for Store 2 is greater than the mode of the data for Store 1.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Suppose a manufacturer finds that 95% of their production is normal but the final 5% has one or more flaws. Each flawed good has
RUDIKE [14]

Answer:

1)    

FLAW                         TYPE2         NO TYPE2 FLAW

TYPE1                         0.015           0.025

NO TYPE1 FLAW        0.01             0.95

2) 0.04 and $0.04

3) 0.025 and $0.025

4) 0.015 and $0.015

5) 0.95 and $0.95

Step-by-step explanation:

Given that;

financial cost = $1

p(flaw) = 0.05  

p(type 1 flaw / flaw) = 80% = 0.8

p(type 2 flaw / flaw) = 50% = 0.5

p( type 1 and 2 flaw/flaw) = 30% = 0.30

1) Bivariate Table

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw)  = 0.05 × 0.5 = 0.025

p( type 1 and 2 flaw) =  p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

p( only 1 flow) = 0.04 - 0.015 = 0.025

p( only 2 flow) =  0.025 - 0.015 = 0.01

THEREFORE  the Bivariate Table;

FLAW                         TYPE2         NO TYPE2 FLAW

TYPE1                         0.015           0.025

NO TYPE1 FLAW       0.01              0.95

2) probability and expectations of type 1 flaw?

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

Expected financial cost to the firm per good = $1 × 0.04 = $0.04

3)  probability and expectation of Type 2 flaw

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw)  = 0.05 × 0.5 = 0.025

Expected financial cost to the firm per good = $1 × 0.025 = $0.025

4) probability and expectations of Type 1 and 2 flaws

p( type 1 and 2 flaw) =  p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

Expected financial cost to the firm per good = $1 * 0.015 = $0.015

5) probability and expectations of no flaws?

Probability of no flaw = P(No flaw) =95% =  0.95

Expected financial cost saved the firm per good due to no flaw

= $1 × 0.95 = $0.95

5 0
3 years ago
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