The answer for the problem is -13x+8
Let 3<em>n</em> + 1 denote the "number" in question. The claim is that
(3<em>n</em> + 1)² = 3<em>m</em> + 1
for some integer <em>m</em>.
Now,
(3<em>n</em> + 1)² = (3<em>n</em>)² + 2 (3<em>n</em>) + 1²
… = 9<em>n</em>² + 6<em>n</em> + 1
… = 3<em>n</em> (3<em>n</em> + 2) + 1
… = 3<em>m</em> + 1
where we take <em>m</em> = <em>n</em> (3<em>n</em> + 2).
18 . it's increasing by 5 every time so the next one after 23 is 28
I think I know what your asking so the answer would be 27/30 and 28/30
A^2+b^2=c^2 so 4(4) +3(3) is 16+9= 25 and the square root of that is 5.
