Question

What is an equation of the line that is parallel to y=9−5x and passes through (0, 8) ?

Answer 1

Answer:

y =  8-5x is equation of line that is parallel to y = 9-5x and passing through (0,8).

Step-by-step explanation:

We have given a equation of line and a point.

y=9−5x and (x₁,y₁)=  (0, 8)

We have to find equation of line that is parallel to given equation of line and passing through given point.

y-y₁ = m(x-x₁) is point-slope form of equation of line where m is slope of line.

Since, we know that parallel line have equal slope of line.

Given equation has slope equal to -5.

Parallel line also has slope equal to -5.

m = -5

Putting values in point-slope form of equation , we have

y-(8) = -5(x-0)

y-8 = -5(x)

y-8= -5x

y =  8-5x is equation of line that is parallel to y = 9-5x and passing through (0,8).

Answer 2

Hello!

The answer is:

$y=8-5x$

Why?

If we want to find an equation of a line parallel to the given line, we must remember that parallel lines has the same slope.

So,

Line equation is:

$y=mx+b$

Where:

$m=LineSlope$

$b=y-axisIntercept$

So, we are given the function:

$y=9-5x$

Where:

m=-5

Also, we are given the point where the line passes through (0,8), we can use it to find "b"

$y=b-5x\\y+5x=b\\b=8+5(0)=8$

So, the equation will be:

$y=8-5x$

To prove if we are right, let's substitute (0,8):

$8=8-5(0)$

$8=8-0$

$8=8$

Have a nice day!