5/6-3/5 + 3/10=
Cfrac%7B3%7D%7B10%7D%20" id="TexFormula1" title=" \frac{5}{6} - \frac{3}{5} + \frac{3}{10} " alt=" \frac{5}{6} - \frac{3}{5} + \frac{3}{10} " align="absmiddle" class="latex-formula">
1 answer:
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Answer:
y +8 = -4(x -8)
Step-by-step explanation:
You recognize that the given equation is in slope-intercept form:
y = mx + b
with m = 1/4 and b = 5.
A perpendicular line will have a slope that is the negative reciprocal of this value of m, so the desired slope is ...
-1/m = -1/(1/4) = -4
The point-slope form of the equation for a line is ...
y -k = m(x -h) . . . . . for slope m through point (h, k)
Using m=-4 and (h, k) = (8, -8), the point-slope form of the equation for the line you want is ...
y +8 = -4(x -8)
