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goblinko [34]
2 years ago
11

A rectangular dance floor has a width of 12 meters and a length of 16 meters. What is the length of a diagonal of the dance floo

r?
Mathematics
1 answer:
lesya692 [45]2 years ago
7 0

Answer:

d=20m

Step-by-step explanation:

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This graph represents the average number of animals that are seen in a veterinarian's office during the day.
defon

Answer:

A. 10 animals seen in 1 hour

C. 60 animals seen in 6 hours

i dont know B sorry

Step-by-step explanation:

6 0
3 years ago
I need help solving this pls
Oksana_A [137]

Answer:

Adding them together. x = 3/2, y = 8

Step-by-step explanation:

Adding because we want to get rid of a variable. If we add, 2x + 6x = 8x, 1/2 * y + (-1/2 * y) = 0, and 7 + 5 = 12. Adding gets rid of the y variable.

By adding we get that 8x = 12 which gives us x = 12/8 = 3/2

Substituting this back into either equation will give us y = 8.

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2 years ago
20 POINTS BRAINLIEST
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Answer:

C

Step-by-step explanation:

Exponential decay should be in this format A = Ao × e^(-kt)

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3 years ago
A lumber company is making boards that are 2920.0 millimeters tall. If the boards are too long they must be trimmed, and if the
Effectus [21]

Answer:

The value of the test statistic is of 0.22.

Step-by-step explanation:

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the expected mean, \sigma is the standard deviation(square root of the variance) and n is the size of the sample.

A lumber company is making boards that are 2920.0 millimeters tall.

This means that \mu = 2920.

A sample of 12 is made, and it is found that they have a mean of 2922.7 millimeters with a variance of 121.00.

This means that X = 2922.7, n = 12, \sigma = \sqrt{121} = 11. So

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{2922.7 - 2922}{\frac{11}{\sqrt{12}}}

t = 0.22

The value of the test statistic is of 0.22.

4 0
2 years ago
A quadratic equation is shown. (x + 6)(x + 2) = x
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Answer:

Option : A

Step-by-step explanation:

Hope it helps you!

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