Answer:
equation :water remaining in pool after 30 mins= 0.027X
answer = 67.5 Gallon
Step-by-step explanation:
Given
quantity of water in pool = 2500 gallon
percentage of water lost every 10 mins = 70%
therefore percentage of water remaining in pool = (100- 70)% = 30%
Let the quantity of water in pool be X gallon
% of water remaining in gallon after 10 mins = 30% of X = 0.3X
% of water remaining in gallon after another 10 mins = 30% of water at 10 mins = 30% of 0.3 X = 0.3 * 0.3X = 0.09 X
% of water remaining in gallon after another 30 mins = 30% of water present at 20 minutes = 30% of 0.09 X = 0.3 * 0.09X = 0.027X
Therefore equation of water remaining after 30 mins is = 0.027 X
Substituting value of initial quantity of water in the above equation we get the volume pf water remaining in pool after 30 mins = 0.027 * 2500
= 67.5 gallons
Part a : company A : 7w+12
Company B: 5w+15
Part B:::
company a would charge $68
and company B would charge $55
(93+67+78+44+123)/5=405/5=81 pizzas per day on average
C is your answer.
1.
a. let k = constant
k = y/x
so k = 14/2 = 7
b. the equation would be y = 7x
2. a. k = y/x = 25/5 = 5
b. y = 5x
c. 50 = 5x, x = 50/5 = 10
Answer:
Option B.
{–9 + i√225 / 24, –9 – i√225 / 24}
Step-by-step explanation:
12a² + 9a + 7 = 0
Using formula method, the solutions to the equation can be obtained as follow:
Coefficient of a² (a) = 12
Coefficient of a (b) = 9
Constant (c) = 7
a = –b ±√(b² – 4ac) / 2a
a = –9 ±√(9² – 4 × 12 × 7) / 2 × 12
a = –9 ±√(81 – 336) / 24
a = –9 ±√(– 225) / 24
Recall
–225 = –1 × 225
Thus,
–9 ±√(– 225) / 24 = –9 ±√(–1 × 225)/24
Recall
√(–1 × 225) = √–1 × √225 = i√225
Thus,
–9 ±√(–1 × 225)/24 = –9 ± i√225/24
Therefore,
a = –9 ± i√225/24
a = –9 + i√225 / 24 or –9 – i√225 / 24
Therefore, the solutions to the equation are:
{–9 + i√225 / 24, –9 – i√225 / 24}