Question

your 2500 gallon pool has sprung a leak and loses 70% of its water every 10 minutes . how much water will remain in the pool after 30 minutes . what is the equation and answer

Answer 1

Answer:

equation :water remaining in pool after 30 mins= 0.027X

answer = 67.5 Gallon

Step-by-step explanation:

Given

quantity of water in pool = 2500 gallon

percentage of water lost every 10 mins = 70%

therefore percentage of water remaining in pool = (100- 70)% = 30%

Let the quantity of water in pool be X gallon

% of water remaining in gallon after 10 mins = 30% of X = 0.3X

% of water  remaining in gallon after another 10 mins = 30% of water at 10 mins = 30% of 0.3 X = 0.3 * 0.3X = 0.09 X

% of water  remaining in gallon after another 30 mins = 30% of water present at 20 minutes = 30% of 0.09 X = 0.3 * 0.09X = 0.027X

Therefore equation of water remaining after 30 mins is = 0.027 X

Substituting value of initial quantity of water in the above equation we get the volume pf water remaining in pool after 30 mins = 0.027 * 2500

                                                                                       = 67.5 gallons