Question

SOLVE FOR X??? mula1" title="\frac{x}{3} +2 =\frac{x}{4}+3" alt="\frac{x}{3} +2 =\frac{x}{4}+3" align="absmiddle" class="latex-formula">

$3(4+2x)=33 - x$

Answer 1

Answer:

$\boxed{ \bold{ \boxed{ \sf{1. \: \: \: \: \: x = 12}}}}$

$\boxed{ \bold{ \boxed{ \sf{2. \: \: \: \: \: x = 3}}}}$

Step-by-step explanation:

$\sf{1. \: \: \: \: \frac{x}{3} + 2 = \frac{x}{4} + 3}$

Move x / 4 to left hand side and change its sign

Similarly, move 2 to right hand side and change it's sign

$\longrightarrow{ \sf{ \frac{x}{3} - \frac{x}{4} = 3 - 2}}$

Take the L.C.M of 3 and 4

L.C.M of 3 and 4 = 12

$\longrightarrow{ \sf{ \frac{x \times 4 - x \times 3}{12} = 3 - 2}}$

$\longrightarrow{ \sf{ \frac{4x - 3x}{12} = 3 - 2}}$

$\longrightarrow{ \sf{ \frac{x}{12} = 3 - 2}}$

Subtract 2 from 3

$\longrightarrow{ \sf{ \frac{x}{12} = 1}}$

Do cross multiplication

$\longrightarrow{ \sf{x = 1 \times 12}}$

$\longrightarrow { \sf{x = 12}}$

--------------------------------------------------------------------

$\sf{2. \: \: \: \: 3(4 + 2x) = 33 - x }$

Distribute 3 through the parentheses

$\longrightarrow{ \sf{12 + 6x = 33 - x}}$

Move x to left hand side and change it's sign

Similarly, move 12 to right hand side and change it's sign

$\longrightarrow{ \sf{6x + x = 33 - 12}}$

Collect like terms

$\longrightarrow{ \sf{7x = 33 - 12}}$

Subtract 12 from 33

$\longrightarrow{ \sf{7x = 21}}$

Divide both sides by 7

$\longrightarrow{ \sf{ \frac{7x}{7} = \frac{21}{7} }}$

Calculate

$\longrightarrow{ \sf{x = 3}}$

Hope I helped!

Best regards! :D