I think Its C because in the frequency table or table given if the heads are counted there are 6 of them and over all 10 which will make 6/10
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Answer:
- 75 adult tickets
- 125 child tickets
Step-by-step explanation:
Let 'a' represent the number of adult tickets sold. Then (200-a) is the number of child tickets sold, and the revenue is ...
8a +5(200 -a) = 1225
3a = 225 . . . . . . . . . . subtract 1000, simplify
a = 75 . . . . . . . . . . . . .divide by 3
200 -a = 125
75 adult ($8) and 125 child ($5) tickets were sold.
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<em>Additional comment</em>
The question asked here is "how many tickets did Kay sell?" The second line of your problem statement tells you the answer: "Kay sold 200 tickets ...". We have assumed that you are interested in the breakdown of tickets sold, even though that is not the question that is asked here.
Answer:
50 miles
Step-by-step explanation:
Multiply the given scale numbers by 1/2 to find your answer:
1/2 in = 100 mi
(1/2)(1/2 in) = (1/2)(100 mi) . . . . multiply the ratio values by 1/2
1/4 in = 50 mi
I can the company sold 3,00 units in 2008, and 5,00 in 2012