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qaws [65]
4 years ago
7

The total scores on the Medical College Admissions Test (MCAT) in 2013 follow a Normal distribution with mean 25.3 and standard

deviation 6.5.
a) what are the median and the first and third quartiles of the MCAT scores? what is the interquartile range?

please i need help!!!
Mathematics
1 answer:
aivan3 [116]4 years ago
8 0
1st quartile (25%) and the 3rd quartile (75%) values are -0.6745 and 0.6745 respectively. Use this formula z= (x-mean)SD -0.6745 = (x-25.3)/6.5. 
x=25.3 - 0.6745(6.5) = 25.3 - 4.3843 = 20.9157 1st Quartile
 0.6745 = (x - 25.3) 6.5
 x = 25.3 + 0.6745 = 25.3 + 4.3843 = 29.6843 3rd quartile 
 interquartile range is the difference between the 1st quartile and the 4th quartile
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PLEASE HELP !!!!
Bess [88]

Answer:

About 31 years

Step-by-step explanation:

Given data

Principal= $3500

Rate=  4.75%

Final amount= $15,000

Time=??

The expression for time on compound interest is

Calculate time, solve for t

t = ln(A/P) / r

substitute

Calculate time, solve for t

t = ln(15000/3500) / 0.0475

t= ln(4.2857)/ 0.0475

t= 1.4552/0.0475

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Hence it will take about 31 years

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3 years ago
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Ok why’s the picture upside down??.?
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Use theorem 7. 4. 2 to evaluate the given laplace transform. do not evaluate the convolution integral before transforming. (writ
irga5000 [103]

With convolution theorem the equation is proved.

According to the statement

we have given that the equation and we have to evaluate with the convolution theorem.

Then for this purpose, we know that the

A convolution integral is an integral that expresses the amount of overlap of one function as it is shifted over another function.

And the given equation is solved with this given integral.

So, According to this theorem the equation becomes the

\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{ \mathscr{L} (e^{-\tau} \cos \tau ) }{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{\frac{s+1}{(s+1)^2+1}}{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{1}{s}\left (\frac{s+1}{(s+1)^2+1} \right).

Then after solving, it become and with theorem it says that the

\mathscr{L} \left( \int_{0}^{t} f(\tau) d\tau \right) = \frac{\mathscr{L} ( f(\tau))}{s} .

Hence by this way the given equation with convolution theorem is proved.

So, With convolution theorem the equation is proved.

Learn more about convolution theorem here

brainly.com/question/15409558

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2 years ago
Find the area of a quarter circle with the radius of 6cm
Ronch [10]

Answer:

28.27cm³

Step-by-step explanation:

Area of a circle:

A=\pi r^2

First, find the area of a full circle with this given radius:

\rightarrow A=(3.14159)(6)^2\\\rightarrow A=(3.14159)(36)\\\rightarrow A=113.09734\\

Now, to find the radius of a quarter circle with the same radius, just divide by 4:

\rightarrow A = \frac{113.09734}{4}\\\rightarrow A = 28.27433

The radius of the quarter circle is about 28.27cm³

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Answer:

d

Step-by-step explanation:

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