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VLD [36.1K]
3 years ago
15

Find the number of possible positive real zeros of f(x)= -7x^4+ 49x^3+ 84x^2.

Mathematics
1 answer:
Solnce55 [7]3 years ago
5 0
B.Two is your answer
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There are 3 consecutive integers. Four times the smallest integer is equal to six more than three times the largest integer. Wha
Aliun [14]

Answer:

5

Step-by-step explanation:

Let the smallest integer equal x - 1, the next one equal x, and the last one equal x + 1.

4(x-1) = 3(x-1) + 6

x-1 = 5

x = 6

The smallest integer is x - 1, which is equal to 5. Thus, the smallest of the three integers is 5.

5 0
3 years ago
How to put this in $799.73 in numeric please help thank you
AlekseyPX
The answer is 800$...
6 0
3 years ago
What is 4•4•4•4•4 in exponential form? And need the answer ASAP
MariettaO [177]

Answer:

It is 4^{5}

Step-by-step explanation:

the four is multiplied 5 times

7 0
3 years ago
Read 2 more answers
PLEASE HELP ME QUICKLY!!! Given that N:{1,2,3,5,8,13} and M:{−9,−8,−6,−4,−2,4}, which statements about N and M are true?
Lelechka [254]

Answer:

The intersection of N and M contains only those elements that are in both N and M.

The intersection of N and M is ϕ.

​N∩M=∅

Step-by-step explanation:

Given

M = { 1, 2, 3, 5, 8, 13}

N = {-9, -8, -6, -4, -2, 4}

Now let us see each statement one by one.

The intersection of N and M contains only those elements that are in both N and M.

The statement is true because by definition intersection of two sets consists of common elements of both sets.

The intersection of N and M is ϕ.

The statement is true. As there is no common element in both sets.

The intersection of N and M is {−9,−8,−6,−4,−2}.

The statement is false because there is not common element in M and N.

N∪M=∅

The statement is false as the union consists of elements of both sets so it can't be empty.

​N∩M=∅

True. Because no common element so intersection will be an empty set..

4 0
3 years ago
Exact = 50 Approximate = 45
Nikitich [7]

Answer:

Approximate of error = 11.11 % (Approx.)

Step-by-step explanation:

Given:

Exact value = 50

Approximate value = 45

Find:

Approximate of error

Computation:

Approximate of error = [(Exact value - Approximate value)/Approximate value]100

Approximate of error = [(50 - 45)/45]100

Approximate of error = [(5)/45]100

Approximate of error = [0.11111]100

Approximate of error = 11.11 % (Approx.)

3 0
3 years ago
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