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Vika [28.1K]
3 years ago
15

If Carol hangs a picture

Mathematics
2 answers:
saul85 [17]3 years ago
7 0

Answer:

Carol will have 1 yard if wire left.

Step-by-step explanation:

11/8 - 3/8 = 8/8

You subtract three from eleven and the right stays the same because you are SUBTRACTING the fractions.

After subtracting, you should simplify 8/8 to 1 unless told not to do so.

8/8 is equal to 1 yard.

Alina [70]3 years ago
5 0

Answer:

3 - 11 = 8      8 - 8 = 0  

i think the answer is 8

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Please help, I didn't learn this in class!
NemiM [27]
Solve the following system using elimination:
{-2 x + 2 y + 3 z = 0 | (equation 1)
{-2 x - y + z = -3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x - 3 y - 2 z = -3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+3 y + 2 z = 3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+3 y + 2 z = 3 | (equation 2)
{0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y+0 z = 5 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)


Divide equation 2 by 5:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:
{-(2 x) + 0 y+3 z = -2 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
v0 x+0 y+z = 0 | (equation 3)


Subtract 3 × (equation 3) from equation 1:
{-(2 x)+0 y+0 z = -2 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:
{x+0 y+0 z = 1 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1, y = 1, z = 0

7 0
3 years ago
Plz help this is timed
LiRa [457]

Answer:

y= 3/2× (-1/2) x=0

Step-by-step explanation:

multiply the equation by both sides by 4/3 and nd then you get 0=x then you swap the sides of the equation x=0 nd your answer is x=0

7 0
3 years ago
PLEASE PLEASE HELP ME NO DOWNLOADABLE FILES<br><br> How many solutions <br> y=2x^2+9x
lisabon 2012 [21]

Answer:

There's going to be 2 solutions

Step-by-step explanation:

7 0
3 years ago
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What is the answer for all these numbers
Leya [2.2K]
3=12
4=13
5=14
6=15
7=16
6 0
3 years ago
2. A man drove 240 miles south at the rate of 60 miles per hour. On the return trip, he drove the rate of 40 miles per hour. The
shutvik [7]

av =  \frac{v_{2} - v_{1}}{t_{2} - t_{1}}

t_{1} =  \frac{d}{v_{1}} =  \frac{240}{60} = 4 \: hours  \\ t_{2} =  \frac{d}{v_{2}}  =  \frac{240}{40}  = 6 \: hours

av =  \frac{v_{2} - v_{1}}{t_{2} - t_{1}}  =  \frac{40 - 60}{6 - 4}   =  \frac{ - 20}{2}  =  - 10

av  \: speed= 10 \\ av \: velocity =  - 10 \:  \: north

3 0
1 year ago
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