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Korolek [52]
4 years ago
13

A store manager timed Janette to see how long it would take her to fold and put away a sweater, a shirt, a pair of pants, and a

scarf. It took her 26.1 seconds for the shirt, 24.3 seconds for the sweater, 32.8 seconds for the pants, and 18.2 seconds for the scarf. What was the average time it took Janette to fold and put away all four items? 25 seconds 25.4 seconds 25.35 seconds 26.1 seconds
Mathematics
2 answers:
HACTEHA [7]4 years ago
9 0

To find the average of numbers you have to add all the numbers and divide by the number of numbers. *confusing*

25 + 25.4 + 25.35 + 26.1 = 101.85

101.85 ÷ 4 = 25.4625

♡ Hope this helped! ♡

❀ 0ranges ❀

pantera1 [17]4 years ago
7 0

Answer:

B

Step-by-step explanation:

25.4

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Answer:

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Step-by-step explanation:

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Find the volume of the solid generated when R​ (shaded region) is revolved about the given line. x=6−3sec y​, x=6​, y= π 3​, and
Dmitrij [34]

Answer:

V=9\pi\sqrt{3}

Step-by-step explanation:

In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).

The formula we will use for this problem is the following:

V=\int\limits^b_a {\pi r^{2}} \, dy

where:

r=6-(6-3 sec(y))

r=3 sec(y)

a=0

b=\frac{\pi}{3}

so the volume becomes:

V=\int\limits^\frac{\pi}{3}_0 {\pi (3 sec(y))^{2}} \, dy

This can be simplified to:

V=\int\limits^\frac{\pi}{3}_0 {9\pi sec^{2}(y)} \, dy

and the integral can be rewritten like this:

V=9\pi\int\limits^\frac{\pi}{3}_0 {sec^{2}(y)} \, dy

which is a standard integral so we solve it to:

V=9\pi[tan y]\limits^\frac{\pi}{3}_0

so we get:

V=9\pi[tan \frac{\pi}{3} - tan 0]

which yields:

V=9\pi\sqrt{3}]

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4. The sail of a boat is in the shape of a right triangle. If the area of the sail is 42 square feet and its base is 12 feet, wh
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3 years ago
Regular hexagon ABCDEF is inscribed in circle X and has an apothem that is 6√3 inches long. Use the length of the apothem to cal
Phantasy [73]

Answer:

Part A

The \ circumradius, \  R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}

Plugging in the given values we get;

The \ circumradius, \  R = \dfrac{6 \cdot \sqrt{3} }{cos \left(\dfrac{\pi}{6} \right)} = \dfrac{6 \cdot \sqrt{3} }{\left(\dfrac{\sqrt{3} }{2} \right)} = 6 \cdot \sqrt{3}  \times \dfrac{2}{\sqrt{3} }  = 12

R = 12 inches

The radius of the circumscribing circle is 12 inches

Part B

The length of each side of the hexagon, 's', is;

s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)

Therefore;

s = 6 \cdot \sqrt{3}  \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3}  \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12

s = 12 inches

The perimeter, P = n × s = 6 × 12 = 72 inches

The perimeter of the hexagon is 72 inches

Step-by-step explanation:

The given parameters of the regular hexagon are;

The length of the apothem of the regular hexagon, a = 6·√3 inches

The relationship between the apothem, 'a', and the circumradius, 'R', is given as follows;

a = R \cdot cos \left(\dfrac{\pi}{n} \right)

Where;

n = The number of sides of the regular polygon = 6 for a hexagon

'a = 6·√3 inches', and 'R' are the apothem and the circumradius respectively;

Part A

Therefore, we have;

The \ circumradius, \  R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}

Plugging in the values gives;

The \ circumradius, \  R = \dfrac{6 \cdot \sqrt{3} }{cos \left(\dfrac{\pi}{6} \right)} = \dfrac{6 \cdot \sqrt{3} }{\left(\dfrac{\sqrt{3} }{2} \right)} = 6 \cdot \sqrt{3}  \times \dfrac{2}{\sqrt{3} }  = 12

The circumradius, R = 12 inches

Part B

The length of each side of the hexagon, 's', is given as follows;

s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)

Therefore, we get;

s = 6 \cdot \sqrt{3}  \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3}  \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12

The length of each side of the hexagon, s = 12 inches

The perimeter of the hexagon, P = n × s = 6 × 12 = 72 inches

The perimeter of the hexagon = 72 inches

5 0
3 years ago
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