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Anuta_ua [19.1K]
3 years ago
13

A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. (If an answer does

not exist, enter DNE.) f(t) = t3 − 8t2 + 27t
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0

The question is not clear, but it is possible to obtain distance, s, from the given function. This, I would show.

Answer:

s = 17 units

Step-by-step explanation:

Given f(t) = t³ - 8t² + 27t

Differentiating f(t), we have

f'(t) = 3t² - 16 t + 27

At t = 0

f'(t) = 27

This is the required obtainaible distance, s.

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Find the sum of the following infinite geometric series, if it exists. 2 + 6 + 18 + 54 +… Does not exist 23,567 25,982 29,034
Sladkaya [172]

Option A: The sum for the infinite geometric series does not exist

Explanation:

The given series is 2+6+18+54+.......

We need to determine the sum for the infinite geometric series.

<u>Common ratio:</u>

The common difference for the given infinite series is given by

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Thus, the common difference is r=3

<u>Sum of the infinite series:</u>

The sum of the infinite series can be determined using the formula,

S_{\infty}=\frac{a}{1-r}   where 0

Since, the value of r is 3 and the value of r does not lie in the limit 0

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Aryabhata, also called Aryabhata I or Aryabhata the Elder, (born 476, possibly Ashmaka or Kusumapura, India), astronomer and the earliest Indian mathematician whose work and history are available to modern scholars. He is also known as Aryabhata I or Aryabhata the Elder to distinguish him from a 10th-century Indian mathematician of the same name. He flourished in Kusumapura—near Patalipurta (Patna), then the capital of the Gupta dynasty—where he composed at least two works, Aryabhatiya (c. 499) and the now lost Aryabhatasiddhanta.

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<h2>Mark as brainlist ❤️❤️</h2>

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