All categories

3 years ago

Divide. Express your answer in lowest terms. - 7/10 divide by (- 4/5)

2 answers:

8 0

$- \frac{7}{10} \div (- \frac{4}{5} ) \\ \\ - \frac{7}{10} \div - \frac{4}{5} \\ \\ - \frac{7}{10} \times \frac{5}{-4} \\ \\ \frac{7}{10} \times \frac{5}{4} \\ \\ \frac{7 \times 5}{10 \times 4} \\ \\ \frac{35}{10 \times 4} \\ \\ \frac{35}{40} \\ \\ \frac{7}{8} \\ \\ Answer: \fbox {7/8} \ or \ \fbox {0.875}$

Aleonysh [2.5K]3 years ago

7 0

-7/10 ÷ (-4/5)

First, we need to do KCF

Keep the first fraction.

-7/10

Change the sign.

-7/10 *

Flip the fraction

-7/10 * (-5/4)

Now multiply!

7*5 = 35
4*10 = 40

Now, simplify

35/5 = 7
40/5 = 8

Final answer: 7/8

You might be interested in

What are the coordinates of the vertex of the function f(x) = x2 - 12x + 5?

FinnZ [79.3K]

Answer:

The vertex is the point (6,-31)

Step-by-step explanation:

we have

$f(x)=x^2-12x+5$

This is a vertical parabola open upward

The vertex represent a minimum

Convert to vertex form

Complete the square

$f(x)=(x^2-12x+6^2)+5-6^2$

$f(x)=(x^2-12x+36)-31$

Rewrite as perfect squares

$f(x)=(x-6)^2-31$ -----> equation in vertex form

therefore

The vertex is the point (6,-31)

6 0

3 years ago

What value of x is in the solution set of 9(2x + 1) < 9x - 18? <br> -4<br> -3<br> -2<br> -1

Anastaziya [24]

Answer:

The only possible answer that is correct is the first one, x = -4.

Step-by-step explanation:

Simplify the given inequality as much as possible, and then substitute each of the given x values one by one to determine which is in the solution set.

9(2x + 1) < 9x - 18 becomes 18x + 9 < 9x - 18, which, if reduced by dividing all four terms by 9, becomes 2x + 1 < x - 2.

Simplifying further, we get x < - 3. The only possible answer that is correct is the first one, x = -4. -4 < -3 is true.

8 0

3 years ago

Read 2 more answers

HERES THIS QUESTION PLEASE HELP

Oxana [17]

27 hours in the maximum hours

7 0

3 years ago

Li Juan solves the equation below by first squaring both sides of the equation.

emmasim [6.3K]

-3w + 13
Happy New Year

8 0

3 years ago

Read 2 more answers

Return to the credit card scenario of Exercise 12 (Section 2.2), and let C be the event that the selected student has an America

Nadya [2.5K]

Answer:

A. P = 0.73

B. P(A∩B∩C') = 0.22

C. P(B/A) = 0.5

P(A/B) = 0.75

D. P(A∩B/C) = 0.4

E. P(A∪B/C) = 0.85

Step-by-step explanation:

Let's call A the event that a student has a Visa card, B the event that a student has a MasterCard and C the event that a student has a American Express card. Additionally, let's call A' the event that a student hasn't a Visa card, B' the event that a student hasn't a MasterCard and C the event that a student hasn't a American Express card.

Then, with the given probabilities we can find the following probabilities:

P(A∩B∩C') = P(A∩B) - P(A∩B∩C) = 0.3 - 0.08 = 0.22

Where P(A∩B∩C') is the probability that a student has a Visa card and a Master Card but doesn't have a American Express, P(A∩B) is the probability that a student has a has a Visa card and a MasterCard and P(A∩B∩C) is the probability that a student has a Visa card, a MasterCard and a American Express card. At the same way, we can find:

P(A∩C∩B') = P(A∩C) - P(A∩B∩C) = 0.15 - 0.08 = 0.07

P(B∩C∩A') = P(B∩C) - P(A∩B∩C) = 0.1 - 0.08 = 0.02

P(A∩B'∩C') = P(A) - P(A∩B∩C') - P(A∩C∩B') - P(A∩B∩C)

= 0.6 - 0.22 - 0.07 - 0.08 = 0.23

P(B∩A'∩C') = P(B) - P(A∩B∩C') - P(B∩C∩A') - P(A∩B∩C)

= 0.4 - 0.22 - 0.02 - 0.08 = 0.08

P(C∩A'∩A') = P(C) - P(A∩C∩B') - P(B∩C∩A') - P(A∩B∩C)

= 0.2 - 0.07 - 0.02 - 0.08 = 0.03

A. the probability that the selected student has at least one of the three types of cards is calculated as:

P = P(A∩B∩C) + P(A∩B∩C') + P(A∩C∩B') + P(B∩C∩A') + P(A∩B'∩C') +

P(B∩A'∩C') + P(C∩A'∩A')

P = 0.08 + 0.22 + 0.07 + 0.02 + 0.23 + 0.08 + 0.03 = 0.73

B. The probability that the selected student has both a Visa card and a MasterCard but not an American Express card can be written as P(A∩B∩C') and it is equal to 0.22

C. P(B/A) is the probability that a student has a MasterCard given that he has a Visa Card. it is calculated as:

P(B/A) = P(A∩B)/P(A)

So, replacing values, we get:

P(B/A) = 0.3/0.6 = 0.5

At the same way, P(A/B) is the probability that a student has a Visa Card given that he has a MasterCard. it is calculated as:

P(A/B) = P(A∩B)/P(B) = 0.3/0.4 = 0.75

D. If a selected student has an American Express card, the probability that she or he also has both a Visa card and a MasterCard is written as P(A∩B/C), so it is calculated as:

P(A∩B/C) = P(A∩B∩C)/P(C) = 0.08/0.2 = 0.4

E. If a the selected student has an American Express card, the probability that she or he has at least one of the other two types of cards is written as P(A∪B/C) and it is calculated as:

P(A∪B/C) = P(A∪B∩C)/P(C)

Where P(A∪B∩C) = P(A∩B∩C)+P(B∩C∩A')+P(A∩C∩B')

So, P(A∪B∩C) = 0.08 + 0.07 + 0.02 = 0.17

Finally, P(A∪B/C) is:

P(A∪B/C) = 0.17/0.2 =0.85

4 0

3 years ago