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AnnZ [28]
3 years ago
14

kirby often forgets to switch the inequity sign when dividing a negative. when solving 3x-10≥x, should kirby collect the variabl

es on the left or the right? why?
Mathematics
1 answer:
sukhopar [10]3 years ago
7 0
You should collect the variable on the left side since you can't have two variables of the same letter on each side.so you would take the variable from the right side and subtract it from the left. So subtract x on both sides. Your new problem is 2x-10 is greater than or equal to 0. Now you add 10 on both sides. Your new problem is 2x is greater than or equal to 10. Now divide by 2 on both sides. Your answer would be x is greater than or equal to 5
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Please help question in the picture
tigry1 [53]
There really isn’t a possible answer since there is not enough information given. Not from what I have learned so far at least, but using common sense, and the process of elimination I would say 30
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3 years ago
Would u let be slide in ur dms u have to be a girl and bi ?
nalin [4]

Answer:

what's scary is, im both,but nO

6 0
3 years ago
Read 2 more answers
In the given figure △ABC ≅△DEC. Which of the following relations can be proven using CPCTC ?
Serhud [2]

Option B:

\overline{A B}=\overline{D E}

Solution:

In the given figure \triangle A B C \cong \triangle D E C.

If two triangles are similar, then their corresponding sides and angles are equal.

By CPCTC, in \triangle A B C \ \text{and}\ \triangle D E C,

\overline{AB }=\overline{DE} – – – – (1)

\overline{B C}=\overline{EC} – – – – (2)

\overline{ CA}=\overline{CD} – – – – (3)

\angle ACB=\angle DCE  – – – – (4)

\angle ABC=\angle DEC  – – – – (5)

\angle BAC=\angle EDC  – – – – (6)

Option A: \overline{B C}=\overline{D C}

By CPCTC proved in equation (2) \overline{B C}=\overline{EC}.

Therefore \overline{B C}\neq \overline{D C}. Option A is false.

Option B: \overline{A B}=\overline{D E}

By CPCTC proved in equation (1) \overline{AB }=\overline{DE}.

Therefore Option B is true.

Option C: \angle A C B=\angle D E C

By CPCTC proved in equation (4) \angle ACB=\angle DCE.

Therefore \angle A C B\neq \angle D E C. Option C is false.

Option D: \angle A B C=\angle E D C

By CPCTC proved in equation (5) \angle ABC=\angle DEC.

Therefore \angle A B C\neq \angle E D C. Option D is false.

Hence Option B is the correct answer.

\Rightarrow\overline{A B}=\overline{D E}

5 0
3 years ago
Evaluate 2 sin 60° + tan 45° + cos²60°​
DerKrebs [107]

Answer:

1.25+√3 or 2.9821 to the nearest ten thousandth.

Step-by-step explanation:

sin 60 = √3/2,  tan 45 = 1 and cos^2 60 = (1/2)^2 = 1/4

So we get 2 *√3/2 + 1 + 1/4

= √3 +  1.25

3 0
3 years ago
Read 2 more answers
Bill is shopping for folders, notebooks, and pencils for the first day of school. A notebook costs 4 times as much as a folder.
spin [16.1K]

<u>Answer:</u>

$14

<u>Step-by-step explanation:</u>

Assuming the cost of folder to be x, then the cost of notebook will be 4 x and the cost of set of pencils will be 2 x.

Cost of the folder = $2

Cost of notebook = 4 × 2 = $8

Cost of pencil = 2 × 2 = $4

Total cost of 1 folder, 1 notebook and 1 set of pencils = $2 + $8 + $4 = $14

4 0
3 years ago
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