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AnnZ [28]
3 years ago
14

kirby often forgets to switch the inequity sign when dividing a negative. when solving 3x-10≥x, should kirby collect the variabl

es on the left or the right? why?
Mathematics
1 answer:
sukhopar [10]3 years ago
7 0
You should collect the variable on the left side since you can't have two variables of the same letter on each side.so you would take the variable from the right side and subtract it from the left. So subtract x on both sides. Your new problem is 2x-10 is greater than or equal to 0. Now you add 10 on both sides. Your new problem is 2x is greater than or equal to 10. Now divide by 2 on both sides. Your answer would be x is greater than or equal to 5
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3. James drives for 5 hours at a certain speed and then for 4 hours at a speed 6 km/h greater than his original speed. If he dri
riadik2000 [5.3K]

Answer:30km/hr

Step-by-step explanation:

Total distance=294km

Speed=s

Distance=d

Time=t

First drive:

t=5

d=s x t

d=s x 5

d=5s

Second drive:

t=4

Speed is 6km/h greater than the first speed

The new speed= s+6

d=4(s+6)

Total distance=294

5s + 4(s + 6)=294

5s + 4s + 24=294

Collect like terms

5s + 4s=294 - 24

9s=270

Divide both sides by 9

9s/9=270/9

s=30

First speed=30km/hr

4 0
3 years ago
(-5f+8)4 use disributive property
GREYUIT [131]

Answer:

-20f+32

Step-by-step explanation:

-5×4=-20 put the x back

4×8=32

3 0
2 years ago
Read 2 more answers
What are the x-intercepts of the graphed function?
Vlad [161]

Answer:

Step-by-step explanation:

d

8 0
3 years ago
Read 2 more answers
Please help me I will give BRAINLIST and a like :))))
Vlada [557]

Answer:

18.75%

Step-by-step explanation:

Hello,

3 students are both female and senior

the total number of students is 7+10+8+5=30

so the probability to select one female senior is 3/30=1/10=0.10

probability to select one female is 16/30=16/30

probability that the student is a senior given that it's female is

=P(female and senior)/P(female)

=1/10*30/16=3/16

hope this helps

5 0
3 years ago
Read 2 more answers
Please answer the followings: W^mW^n=
Lunna [17]

Step-by-step explanation:

W^m=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{m}\\\\W^n=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{n}\\\\W^mW^n=\underbrace{(W\cdot W\cdot W\cdot...\cdot W)}_{m}\underbrace{(W\cdot W\cdot W\cdot...\cdot W)}_{n}\\\\=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{m+n}=W^{m+n}

5 0
3 years ago
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