All categories

2 years ago

Billy Bob spend $15 for 20 pokemon cards, how much will he spend for 75 Pokemon cards?

Mathematics

2 answers:

antiseptic1488 [7]2 years ago

7 0

Answer:

60 dollars.

Step-by-step explanation:

Cross multiply. 15 * 75 = 1200

1200/20 = 60

You would pay 60 dollars for 75 pokemon cards.

Likurg_2 [28]2 years ago

3 0

$56.25

$15 ÷ 20 cards = $.75 per card

$.75 × 75 cards = $56.25

You might be interested in

Which number checks the equation 6x = x + 50?

galina1969 [7]

The answer is 10. You are welcome

7 0

2 years ago

Angle A measures 50 degrees. If angle A is rotated 45 degrees, what is the measure of angle A

drek231 [11]

I believe 95 degrees?

4 0

2 years ago

Read 2 more answers

Jeremy is flying his kite. He runs 100 feet away from his house and lets out 75 feet of string. The angle of elevation from the

mel-nik [20]

Answer:

96.36

Step-by-step explanation:

3 0

2 years ago

One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides

Elina [12.6K]

<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

The side of the square is 10 ft.
One of the vertices of an equilateral triangle is on the vertex of a square.
Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

$\mathbf{(1)} \ x^2=100+y^2$

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

$y+(10-y)=10$

Therefore, for Triangle 3, we have that by Pythagorean theorem:

$(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2$

Matching equations (1) and (2):

$2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0$

Using quadratic formula:

$y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68$

Finding x from (1):

$x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft$

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0

2 years ago

Read 2 more answers

Reese pick two numbers, X and Y. she told her friend that the sum of the two numbers is 9 and the difference of the two numbers

jonny [76]

A.
x + y = 9
x - y = 17

b.
$x = 9 - y$
Substitute that into
$9 - y - y = 17 \\ 9 - 2y = 17 \\ 2y = - 8 \\ y = - 4$

Substitute that into
$x = 9 - ( - 4) \\ x = 13$

x = 13, y = - 4

Hope this helps. - M

7 0

2 years ago