We know that
<span>on an analog clock
60 minutes is equal to a circumference of 360</span>°
so
360/60-----> 6°
that means
1 minute is equal to --------> 6°
16 minutes----------> X
x=16*6-----> 96°
the length of a circumference=2*pi*r
for r=8 in
the length of a circumference=2*pi*8-----> 50.24 in
if 360° (full circle) has a length of----------------> 50.24 in
96°---------------------------> x
x=96*50.24/360------> x=13.40 in
the answer is
13.40 in
2(x+y)=24
2x=y
Use substitution. If y=2x, than we can substitute 2x for it in the other equation, because x and y equal the same things in both equations.
So using that we get 2(x+2x)=24
SIMPLIFY
2(3x)=24
DISTRIBUTE
6x=24.
DIVIDE: x=4.
If we substitute x into the original equations we get x=4 and y=8. Those are your two numbers.
Have a nice day! :)
The first one is c because if you put it at negative 1/8 then it is 0-1/8 or 1/8 away from zero
second one is
the
reciprocal is the number that when multiiplied by the number you are
trying to find the reciprocal of, you get +1 so the number you have is
2/7 so
2/7 times x=+1
multiply both sdies by 7/2 to clear fraction
x=+7/2
the reciprocal is +7/2 or +3 and 1/2 which is D
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
The minimum here is negative one half and the maximum is negative ten.
