First thing you should do is reduce coefficients.
1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6
2nd equation has multiples of 5. Divide by 5.
---> x - y = 2
Now elimination part is easier.
Eliminate 'x' variable by subtracting 2nd equation from 1st.
x + 3y = -6
-(x - y = 2)
----------------------
4y = -8
Solve for 'y'
4y = -8
y = (-8)/4 = -2
Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0
Solution to system is:
x=0, y =-2
Answer:
This proves that f is continous at x=5.
Step-by-step explanation:
Taking f(x) = 3x-1 and
, we want to find a
such that 
At first, we will assume that this delta exists and we will try to figure out its value.
Suppose that
. Then
.
Then, if
, then
. So, in this case, if
we get that
. The maximum value of delta is
.
By definition, this procedure proves that
. Note that f(5)=14, so this proves that f is continous at x=5.
20 liters. If there’s 8 liters every 2 days, 8 divided by 2 is 4. 4x5 is 20 liters.
Answer:
1:none
2:c
3:b
4:a
Step-by-step explanation:
<span>(x+3)^2 = x^2 + 69
x^2 + 6x + 9 = x^2 + 69
x^2 + 6x + 9 - x^2 = x^2 + 69 - x^2
6x + 9 = 69</span>