Solution: We are given:

Let
be the weight (oz) of laptop
We have to find 
To find the this probability, we need to find the z score value.
The z score is given below:



Now, we have to find 
Using the standard normal table, we have:

0.9236 or 92.36% of laptops are overweight
Answer:
volume = 338 x 20 = 6760 cm^3
Step-by-step explanation:
large rectangular top area = 14 x 22 = 308 cm^2
small rectangular top area = 6x5 = 30 cm^2
total top area = 308 + 30 = 338 cm^2
volume = 338 x 20 = 6760 cm^3
10/6 = 1 2/3
This is because 5 + 5 =10/6
Divide 19 by six.
This gives you 1 2/3
Payment on Plan A = $300
x is the number of hours Jake works.
Payment on Plan B = Fixed charges + (charge per hour) × (number of hours worked)
= $150 + $6.25(x)
= 150 + 6.25x
Since, the payment on Plan B should be more than Plan A,
150 + 6.25x > 300
6.25x > 300 - 150
6.25x > 150

x > 24
The minimum vale for x which satisfies this inequality is 25.
Hence, x = 25.