Question

(10x2 + 99x – 5) ÷ (x + 10) =

Answer 1

The answer to this problem is 10x - 1 with a 5 reminder, which can also be written as 10x - 1 + 5/(x + 10).

To find this, we first have to turn it into a long division problem. First we look to see how many times x goes into 10x^2.

10x^2/x = 10x.

Now we eliminate the first term and multiply the 10x by the second term.

10x * 10 = 100x.

We now subtract that 100x from 99x. This gives us a -x remainder. We can now see how many times x goes into that as well.

-x/x = -1

This gives us the final answer of 10x - 1 with a 5 remainder.

Answer 2

The answer is 15+99x
______
x+10