The answer to this problem is 10x - 1 with a 5 reminder, which can also be written as 10x - 1 + 5/(x + 10).
To find this, we first have to turn it into a long division problem. First we look to see how many times x goes into 10x^2.
10x^2/x = 10x.
Now we eliminate the first term and multiply the 10x by the second term.
10x * 10 = 100x.
We now subtract that 100x from 99x. This gives us a -x remainder. We can now see how many times x goes into that as well.
-x/x = -1
This gives us the final answer of 10x - 1 with a 5 remainder.
