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vlabodo [156]
4 years ago
13

Which is the estimate of 2584?

Mathematics
1 answer:
Tema [17]4 years ago
8 0
Not quite sure about the answer...maybe we should look for some better like problems....overall, Good luck. I'm sorry I tried to think the best I can..
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NY DMV Knowledge Test / Class D at Home
natima [27]

Answer: A

Step-by-step explanation: This sign should be shown one-half a mile before the working area, just in case they have to detour to another route.

4 0
3 years ago
Line l was mapped to Line m as shown in the graph below. please help
steposvetlana [31]
Line I was translate up 5 units
5 0
3 years ago
Find all x and y intercepts of the graph of the function f(x)= 2x^3+6x^2-2x-6
topjm [15]

9514 1404 393

Answer:

  • y-intercept: (0, -6)
  • x-intercepts: (-3, 0), (-1, 0), (1, 0)

Step-by-step explanation:

We notice the first pair of coefficients is the same as the last pair (with the sign changed). This means we can factor by grouping.

  f(x) = (2x^3 +6x^2) -(2x +6)

  f(x) = 2x^2(x +3) -2(x +3)

  f(x) = 2(x^2 -1)(x +3) = 2(x -1)(x +1)(x +3)

The factors are made to be zero when x is 1, -1, or -3.

The x-intercepts are (1, 0), (-1, 0), (-3, 0).

The y-intercept is the constant, -6.

4 0
3 years ago
Find the length of the following​ two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16
andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)}     dt

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)}     dt

Doing the operations inside of the brackets the derivatives are:

1 ) (\frac{d((1/2)t^2)}{dt} )^2= t^2

2) \frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1

Entering these values of the integral is

r(t)= \int\limits^{16}_{0}  \sqrt{t^2 +2t+1}     dt

It is possible to factorize the quadratic function and the integral can reduced as,

r(t)= \int\limits^{16}_{0} (t+1)  dt= \frac{t^2}{2} + t

Thus, evaluate from 0 to 16

\frac{16^2}{2} + 16

The value is r= 144 units

5 0
4 years ago
It takes Jill 2 hours to run 14.5 miles. At this rate, how far could she run in 3 hours?
Simora [160]

Answer:

Step-by-step explanation:

So we can just set up a proportion

14.5/2=x/3

we can cross multiply

so that means

2x=43.5

x=21.75

3 0
3 years ago
Read 2 more answers
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