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3 years ago

What does 1.4[8(28+35)] equal

Mathematics

2 answers:

Nina [5.8K]3 years ago

7 0

Answer:

The answer is 126

Step-by-step explanation:

(1/4) * (8 * (28 + 35) = 126

tester [92]3 years ago

5 0

Answer:

126

Step-by-step explanation:

this is the answer for the pic

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Brainliest + [20] Points!!!! Explain!

Elena L [17]

Answer: 165 combination can be possible.

Step-by-step explanation:

Here, According to the question,

Different types of machines in the weight room in gym = 11

And, . Geoff has time to use only 3 of them this afternoon.

Therefore, total number of different combination of machine can geoff choose from to use

= $11_C_3$

= $\frac{11!}{3!\times (11-3)! }$ ( because $n_C_r = \frac{n!}{r!(n-r)!}$ )

= $\frac{11!}{3!\times 8! }$

= $\frac{11\times 10\times 9\times 8!}{6\times 8! }$

= $\frac{11\times 10\times 9}{6}$

= $\frac{990}{6}$

= $165$

5 0

3 years ago

-3× + 33= -12 ×= whats the answerr

Lena [83]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A cone and a cylinder have the same radius and height. The volume of the cone is 100π (pi) cubic feet. What is the volume of the

murzikaleks [220]

Answer:

The volume of the cylinder is $300\pi$ cubic feet.

Step-by-step explanation:

From Geometry we remember that volumes of a cone and a cylinder with the same radius ( $R$ ), measured in feet, and height ( $h$ ), measured in feet, are defined by the following equations:

Cone

$V_{co} = \frac{1}{3}\pi\cdot R^{2}\cdot h$ (1)

Cylinder

$V_{cy} = \pi\cdot R^{2}\cdot h$ (2)

The ratio of the volume of the cylinder to the volume of the cone is:

$\frac{V_{cy}}{V_{co}} = 3$ (3)

If we know that $V_{co} = 100\pi\,ft^{3}$ , then the volume of the cylinder is:

$V_{cy} = 3\cdot V_{co}$

$V_{cy} = 300\pi\,ft^{3}$

The volume of the cylinder is $300\pi$ cubic feet.

3 0

3 years ago

Help evaluating the indefinite integral

Dafna11 [192]

Answer:

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

General Formulas and Concepts:
Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle (cu)' = cu'$

Derivative Property [Addition/Subtraction]:
$\displaystyle (u + v)' = u' + v'$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]:
$\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]:
$\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution/u-solve.

Set u:
$\displaystyle u = 4 - x^2$
[u] Differentiate [Derivative Rules and Properties]:
$\displaystyle du = -2x \ dx$
[du] Rewrite [U-Solve]:
$\displaystyle dx = \frac{-1}{2x} \ du$

Step 3: Integrate Pt. 2

[Integral] Apply U-Solve:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du$
[Integrand] Simplify:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du$
[Integral] Rewrite [Integration Property - Multiplied Constant]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du$
[Integral] Apply Integration Rule [Reverse Power Rule]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C$
[u] Back-substitute:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$