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True [87]
3 years ago
15

What does 1.4[8(28+35)] equal

Mathematics
2 answers:
Nina [5.8K]3 years ago
7 0

Answer:

The answer is 126

Step-by-step explanation:

(1/4) * (8 * (28 + 35) = 126

tester [92]3 years ago
5 0

Answer:

126

Step-by-step explanation:

this is the answer for the pic

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The midpoint of ab is m(5-2). If the coordinates of a are (6,-5), what are the coordinates of b
Alex
The coordinate of B is (4,1)
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3 years ago
Can you help me please ​
Olenka [21]

Answer:

log_372 = 3.8928

Step-by-step explanation:

Given

log_38 = 1.8928

Required

Evaluate log_372

We have:

log_372 = log_3(8 *9)

Apply law of logarithm

log_372 = log_38 +log_39

Express 9 as 3^2

log_372 = log_38 +log_33^2

Evaluate the exponents

log_372 = log_38 +2log_33

log_33 = 1.

So:

log_372 = log_38 + 2 * 1

log_372 = log_38 + 2

Substitute log_38 = 1.8928

log_372 = 1.8928 + 2

log_372 = 3.8928

5 0
3 years ago
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
Find the greatest number of sweaters she can buy
rusak2 [61]
She can buy 22 sweaters
3 0
4 years ago
Read 2 more answers
72-12+36 divided by 3+14•8
kupik [55]

Answer:

I got 1.25

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
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