Ask question

Ask question

All categories

schepotkina [342]

3 years ago

5

A football team has 26 players. How many more players should the coach recruit to meet his goal of having 32 players on the team

?

2 answers:

Elanso [62]3 years ago

8 0

6 more playersssssss

harkovskaia [24]3 years ago

4 0

32-26=6 he needs to recruits 6 more players

You might be interested in

The total number of degrees in the center is 360 if all five vertex angles meeting at the center are congruent what is the measu

Rina8888 [55]

Answer:

the answer is 72

7 0

2 years ago

2.58, 2 5/8, 2.6, 2 2/3 least to greatest

8090 [49]

Answer:

2.58, 2.6, 2 5/8, 2 2/3

Step-by-step explanation:

2.58, 2.6, 2 5/8 can be converted into 2.625, and 2 2/3 can be converted into 2.66 with 6 being repeated over & over.

3 0

3 years ago

It takes 27 pounds of seed to completely plant a 3-acre field. How many pounds of seed are needed per acre?

Ray Of Light [21]

Answer:

9 pounds of seed per acre.

Step-by-step explanation:

All you have to do is division. It takes 27 pounds of seed to make 3 acres, so 27 divided by 3. That gives you 9.

5 0

3 years ago

Evaluate cos(sin^-1(4/5)

PSYCHO15rus [73]

Step-by-step explanation:

$Let \: \: \theta = \sin^{ - 1} (\frac{4}{5}) \\ \\ \therefore \: \sin\theta = \frac{4}{5} \\ \\ \because \: { \cos}^{2} \theta =1 - { \sin}^{2} \theta \\ \\ \therefore \: { \cos}^{2} \theta = 1 - (\frac{4}{5} )^{2} \\ \\ = 1 - \frac{16}{25} \\ \\ = \frac{25 - 16}{25} \\ \\ = \frac{9}{25} \\ \\ \therefore \:{ \cos}\theta = \pm \: \frac{3}{5} \\ \\ \because \: \theta \: lie \: in \: the \: first \: quadrant \\ \\ \therefore \: { \cos}\theta = \: \frac{3}{5} \\ \\ \implies \theta = { \cos}^{ -1 } \: \frac{3}{5}\\\\\implies \theta = { \cos}^{ -1 } \: \frac{3}{5}= { \sin}^{ -1 } \: \frac{4}{5} \\ \\ \therefore \: \cos( \ {sin}^{ - 1} \frac{4}{5} ) \\ \\ = \cos( \ {cos}^{ - 1} \frac{3}{5} ) \\\\ = \frac{3}{5} \\ \\ \purple{ \boxed{\therefore \: \cos( \ {sin}^{ - 1} \frac{4}{5} ) = \frac{3}{5}}}$

8 0

3 years ago

Factor the expression using the GCF. The expression 21m−49n factored using the GCF is...

Roman55 [17]

Answer: 7(3m - 7n)

<u>Step-by-step explanation:</u>

Factor each term then see what value(s) they have in common:

21m - 49n

∧ ∧

3 · 7 · m 7 · 7 · n

Both terms have a 7 in common. What is left over after removing the 7?

21m: 7(3m)

49n: 7(7n)

GCF: 7 Leftovers: 3m <em>and</em> 7n

Factored form of expression is: 7(3m - 7n)

6 0

2 years ago

Read 2 more answers