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Savatey [412]
3 years ago
10

120 miles in 2 hours is a....

Mathematics
2 answers:
solmaris [256]3 years ago
6 0

i think part to part

Levart [38]3 years ago
4 0
Part to part . I hope that helps!
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After he finished breakfast, Mr. Edwards left for work at fifteen minutes after seven. what time is this? Use a.m. or p.m.
Alex Ar [27]
7:15 AM

it is 15 minutes after 7 so 7:00 + 0:15 = 7:15
also breakfast is eaten in the morning so AM is right
6 0
3 years ago
Write $2.161616 as a fraction and mixed number
Alona [7]
Fraction is 2.161616/1000000
mixed number is 2 161616/1000000
4 0
3 years ago
On Halloween 4 friends each received 4⁄5 of a pound of candy. How much candy did they receive total?
Leokris [45]

Answer:

16/5 or 3 1/5

Step-by-step explanation:

Your equation would be 4/5*4 which equals 16/5

4 0
3 years ago
Write an equation of the line that is perpendicular to the line y = 1 2 x + 8 that passes through the point (4,6).
Harlamova29_29 [7]
B. 

This is because perpendicular lines have opposite and flipped slopes. 
4 0
3 years ago
Given: m space measured angle space C space equals space 76, a = 20, and b = 13. What is the length of c to the nearest tenth?
Komok [63]

Based on the given parameters, the length of c is 8.0 units

<h3>How to determine the side length of c?</h3>

The given parameters are

Angle c = 76 degrees

Side a = 20

Side b = 13

The length of c is then calculated using the following law of sines

c^2 = a^2 + b^2 - 2absin(C)

Substitute the known values in the above equation

So, we have

c^2 = 20^2 + 13^2 - 2 * 20 * 13 * sin(76)

Express 20^2 as 400

c^2 = 400 + 13^2 - 2 * 20 * 13 * sin(76)

Express 13^2 as 169

c^2 = 400 + 169 - 2 * 20 * 13 * sin(76)

Evaluate the product and sin(76)

c^2 = 400 + 169 - 520 * 0.9703

Evaluate the product

c^2 = 400 + 169 - 504.55

Evaluate the exponents

c^2 = 400 + 169 - 504.55

So, we have

c^2 = 64.45

Evaluate the square root

c = 8.0

Hence, the length of c is 8.0 units

Read more about law of sines at:

brainly.com/question/16955971

#SPJ1

5 0
2 years ago
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