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KonstantinChe [14]
3 years ago
7

Y=x^2-2x-1 and y=-3x+5 solved algebraically

Mathematics
1 answer:
eduard3 years ago
3 0

Answer:

Step-by-step explanation:

y=x²-2x-1

and y=-3x+5

x²-2x-1=-3x+5

x²+x-6=0

x²+3x-2x-6=0

x(x+3)-2(x+3)=0

(x+3)(x-2)=0

x=-3,2

when x=-3

y=-3×-3+5=9+5=14

when x=2

y=-3×2+5=-6+5=-1

so solutions are (-3,14) and (2,-1)

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Vector u has initial point at (3, 9) and terminal point at (–7, 5). Vector v has initial point at (1, –4) and terminal point at
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