What is the slope of a line parallel to a line whose equation is 4y-6y=15

Problem 3

Ilia_Sergeevich [38]

Problem 1 Answer: $x=10$

Simplify both sides of the equation

$(2)(x)+(2)(-3)=14(Distribute)$

$2x+-6=14$

$2x-6=14$

Add 6 to both sides

$2x-6+6=14+6$

$2x=20$

Divide both sides by 2

$2x/2=20/2$

$x=10$

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Problem 2 Answer: $x=-7$

Simplify both sides of the equation

$(-5)(x)+(-5)(-1)=40(Distribute)$

$-5x+5=40$

Subtract 5 from both sides

$-5x+5-5=40-5$

$-5x=35$

Divide both sides by -5

$-5x/5=35/-5$

$x=-7$

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Problem 3 Answer: $x=-8$

Simplify both sides of the equation

$(12)(x)+(12)(10)=24(Distribute)$

$12x+120=24$

Subtract 120 from both sides

$12x+120-120=24-120$

$12x=-96$

Divide both sides by 12

$12x/12=-96/12$

$x=-8$

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Problem 4 Answer: $x=-1/2$

Move all terms to the left:

$2(x+6)-(11)=0$

Multiply parentheses

$2x+12-11=0$

Add all the numbers together, and all the variables

$2x+1=0$

Move all terms containing x to the left, all other terms to the right

$2x=-1\\x=-1/2$

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Problem 5 Answer: $x = 44$

3 0

3 years ago

Read 2 more answers

Find the y-intercept of the line on the graph

Kitty [74]

The Y-intercept is -4 because it's located on the y-axis you can remember that the y-axis is up and down the x-axis is side to side.

7 0

3 years ago

Which equation would give the graph below? (photo)

emmasim [6.3K]

Answer:

C

Step-by-step explanation:

Y= 4^2 - 5 x 4 + 4 = 0

5 0

3 years ago

Identify the dependent variable in this situation:

NNADVOKAT [17]

Amount of data you use is the dependent variable because it depends on how much you will pay

6 0

3 years ago

Total world consumption of iron was approximately 900 million tons in 1993. If consumption had increased by 2.5% each year and t

Lilit [14]

Step-by-step explanation:

We can model the annual consumption of iron by the equation

c = 900 million tons x $1.025^n$ , where

n is the number of years after 1993 and

c is the consumption for that year.

An estimate for the total consumption of iron can now be obtained by integrating this equation with respect to a dummy variable, x from 0 to n.

$C = 900*10^6* \int\limits^n_0 {1.025^x} \, dx$

This equation simplifies to

C = 900 million tons x (1.025^n - 1) / ln(1.025), where

x is a dummy variable and

C is the total consumption of iron n years after 1993.

Let R be the amount of iron remaining at n years after 1993, so

R = 480 billion tons - C

R = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

We need to find the value of n when R is 0, so

0 = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

Simplify this equation to obtain

n = 107.4

So the iron will run out in the year 1993 + 107 = 2100

6 0

3 years ago