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notsponge [240]

4 years ago

11

chef Diana purchase 10 1/2 pounds of beef and 5 1/2 pounds of pork to make meatloaf for her restaurant on the weekend she uses 1

3 2/3 pound of meat how much does he have left

1 answer:

natita [175]4 years ago

3 0

Add the total purchase then subtract the used amount from it. U'll get 2 1/3.

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Darina [25.2K]

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5 0

3 years ago

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Archy [21]

Answer:

3.6 cubic feet

Step-by-step explanation:

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4 0

2 years ago

Find the number of students who like both peanut butter and jam. *

netineya [11]

Answer:

4 students

Step-by-step explanation:

As shown in the diagram, let U=[The total number of students questioned]

$\implies n(U) = 10$

A=[Those who liked peanut butter ]

$\implies n(A) =18$

B=[Those who liked jam ]

$\implies n(B) = 10$

x = those who like both peanut butter and jam.

Also 6 liked neither peanut butter nor jam.

From the diagram we can write the mathematical equation as follow and solve for x

$30 = 18 - x + x + 10 - x + 6$

$\implies 30 = 34- x$

We add x and subtract 30 to both sides.

$\implies 30 - 30 + x = 34- x + x - 30$

$\implies x = 4$

Therefore 4 students like both peanut butter and jam.

6 0

3 years ago

Assume that the number of customers who arrive at a water ice stand follows the Poisson distribution with an average rate of 6.4

Nady [450]

Answer:

18.88% probability that three or four customers will arrive during the next 30 minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Average rate of 6.4 per 30 minutes.

This means that $\mu = 6.4$

What is the probability that three or four customers will arrive during the next 30 minutes?

$P = P(X = 3) + P(X = 4)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 3) = \frac{e^{-6.4}*(6.4)^{3}}{(3)!} = 0.0726$

$P(X = 4) = \frac{e^{-6.4}*(6.4)^{4}}{(4)!} = 0.1162$

$P = P(X = 3) + P(X = 4) = 0.0726 + 0.1162 = 0.1888$

18.88% probability that three or four customers will arrive during the next 30 minutes

4 0

4 years ago

Find the values of c and d

forsale [732]

$36 + 3c = 90 \\ 3c = 90 - 36 \\ 3c = 54 \\ c = 18$

$5d + 10 = 90 \\ 5d = 90 - 10 \\ 5d = 80 \\ d = 16$

4 0

4 years ago