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777dan777 [17]
3 years ago
8

In a sports equipment locker, there are 81 balls and 45 baseball mitts. Write the ratio of balls to baseball

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0

Answer: 9:5

Step-by-step explanation:

81:45 I first just divided them both by three and got 27:15 then they were both divisible by 3 so then I got 9:5

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Luke’s basketball team went to an amusement park at the end of the season. The cost of the admission for 5 coaches and 12 player
Finger [1]

Answer:

The admission cost for each player was <u>22.50</u>.

Step-by-step explanation:

Given:

Luke’s basketball team went to an amusement park at the end of the season.

The cost of the admission for 5 coaches and 12 players was 407.50.

The admission cost for each coach was 27.50.

Now, to find the admission cost for each player.

Total admission cost = 407.50.

Number of coaches = 5.

Admission cost for each = 27.50.

So, the cost of admission of all coaches:

27.50\times 5

=137.50.

Then, we deduct the cost of admission of all coaches from the total admission cost:

407.50-137.50

=270.

<em>Remaining cost = 270.</em>

Number of player = 12.

Now, to get the admission cost for each player we divide the remaining cost  by number of players:

270\div 12

=22.50.

Therefore, the admission cost for each player was 22.50.

7 0
2 years ago
Surface Area = <br><br><br> 96 ft2<br><br><br> 160 ft2<br><br><br> 88 ft2
TEA [102]

Answer:

16 total square units ig

7 0
2 years ago
Who wanna play among us
blondinia [14]

Answer:

I do pls

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3
Whitepunk [10]

If f(x)=4x-3:

\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4

If f(x)=4x^{-3}:

\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}

\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}

\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}

7 0
3 years ago
Write the equation of a rational function g(x) with vertical asymptotes at x = -3 and x = 3 , a horizontal asymptote at y = -4 a
Bezzdna [24]

Answer:

The equation for rational function for given asymptotes is

f(x)=(-4x^2-6)/{(x-3)(x+3)}

Step-by-step explanation:

Given:

vertical Asymptotes at x=3 and x=-3 and a horizontal asymptote at

y=-4 i.e parallel  to x axis.

To find:

equation of a rational function i.e function in form p/q

Solution;

the equation should be in form of p/q

Numerator :denominator.

Consider f(x)=g(x)/h(x)

as vertical asymptote are x=-3 and x=3

denominator becomes, (x-3) and (x+3)

for horizontal asymptote to exist there should have same degrees  in numerator and denominator which of '2'

when g(x) will be degree '2' with -4 as coefficient and dont have  any real.

zero.

By horizontal asymptote  will be (-4x^2 -6)

The rational function is given by

f(x)=g(x)/h(x)

={(-4x^2-6)/(x-3)(x+3)}.

3 0
2 years ago
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