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ValentinkaMS [17]
3 years ago
5

Melissa's employer matches retirement funds 1:2 up to 6% of salary. She makes $55,000 per year. How much should she contribute t

o the 401(k)?
Mathematics
1 answer:
gtnhenbr [62]3 years ago
3 0

Answer: $1100

Step-by-step explanation:

The employer contributes, along with Melissa, in the ratio of 1:2

Up to 6% of $55000, therefore 6/100 x 55000 = 3300

Split in the ratio of 1:2, she will contribute 1/3 of 3300 = 1100

and the employer will contribute 2/3 of 3300 = 2200

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Y=4x+8forx <br> Thank you if you can answer
yKpoI14uk [10]

Answer:

y=4x-8. y=4x−8 y = 4 x -

Step-by-step explanation:

I think is it

7 0
3 years ago
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6-2x=3+5x <br> Solve for x
evablogger [386]

Answer:

x=3/7

Step-by-step explanation:

6-2x=3+5x

subtract 5x from both sides

6-2x-5x=3

subtract 6 from both sides

-2x-5x=3-6

add like terms

-7x=-3

divide both sides by -7

x=3/7

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3 years ago
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What is the distance between the two points shown below?
Mkey [24]

Answer:

distance =  \sqrt{ {( - 3 - ( - 3))}^{2}  +  {(4 - 0)}^{2} }  \\  =  \sqrt{16}  \\  = 4 \: units

5 0
3 years ago
A large tank is filled to capacity with 600 gallons of pure water. brine containing 4 pounds of salt per gallon is pumped into t
nignag [31]
If A(t) is the amount of salt in the tank at time t, then the rate at which the amount of salt in the tank changes is given by

\dfrac{\mathrm dA(t)}{\mathrm dt}=\dfrac{4\text{ lbs}}{1\text{ gal}}\dfrac{6\text{ gal}}{1\text{ min}}-\dfrac{A(t)\text{ lbs}}{600\text{ gal}}\dfrac{6\text{ gal}}{1\text{ min}}
\dfrac{\mathrm dA}{\mathrm dt}=24\dfrac{\text{lb}}{\text{min}}-\dfrac{A(t)}{100}\dfrac{\text{lb}}{\text{min}}

Let's drop the units for now. We have

\dfrac{\mathrm dA(t)}{\mathrm dt}+\dfrac{A(t)}{100}=24
e^{t/100}\dfrac{\mathrm dA(t)}{\mathrm dt}+e^{t/100}\dfrac{A(t)}{100}=24e^{t/100}
\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/100}A(t)\right]=24e^{t/100}
e^{t/100}A(t)=\displaystyle24\int e^{t/100}\,\mathrm dt
e^{t/100}A(t)=2400e^{t/100}+C
A(t)=2400+Ce^{-t/100}

We're given that the water is pure at the start, so A(0)=0, giving

A(0)=0=2400+Ce^{-0/100}\implies C=-2400

So the amount of salt in the tank (in lbs) at time t is

A(t)=2400\left(1-e^{-t/100}\right)
4 0
3 years ago
Without exponents<br> logc (xy^6z^-4) what is the equivalent expression
Sever21 [200]

By eliminating exponents, the <em>logarithmic</em> expression \log_{c} x\cdot y^{6}\cdot z^{-4} is equivalent to the <em>logarithmic</em> expression \log_{c} x + 6\cdot \log_{c} y - 4\cdot \log_{c} z.

<h3>How to simplify logarithmic functions</h3>

In this problem we are supposed to eliminate all exponents of a <em>logarithmic</em> function by applying any of the following properties:

  1. ㏒ x · y = ㏒ x + ㏒ y
  2. ㏒ x/y = ㏒ x - ㏒ y
  3. ㏒ yˣ = x · ㏒ y

Now, we proceed to simplify the function:

\log_{c} x\cdot y^{6}\cdot z^{-4}

\log_{c} x + \log_{c} y^{6} + \log_{c} z^{-4}

\log_{c} x + 6\cdot \log_{c} y - 4\cdot \log_{c} z

By eliminating exponents, the <em>logarithmic</em> expression \log_{c} x\cdot y^{6}\cdot z^{-4} is equivalent to the <em>logarithmic</em> expression \log_{c} x + 6\cdot \log_{c} y - 4\cdot \log_{c} z.

To learn more on logarithms: brainly.com/question/24211708

#SPJ1

5 0
2 years ago
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