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ValentinkaMS [17]

3 years ago

5

Melissa's employer matches retirement funds 1:2 up to 6% of salary. She makes $55,000 per year. How much should she contribute t

o the 401(k)?

1 answer:

gtnhenbr [62]3 years ago

3 0

Answer: $1100

Step-by-step explanation:

The employer contributes, along with Melissa, in the ratio of 1:2

Up to 6% of $55000, therefore 6/100 x 55000 = 3300

Split in the ratio of 1:2, she will contribute 1/3 of 3300 = 1100

and the employer will contribute 2/3 of 3300 = 2200

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Simplify the following expression.

o-na [289]

Answer:

i dont know what you mean but

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3 years ago

Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

so

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

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3 years ago

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7 0

3 years ago

Vector u has its initial point at (-7,2) and it's terminal point at (11,-5). Vector v has a direction opposite that of vector u,

PSYCHO15rus [73]

Answer:

$3\vec{v} = ( - 21,54)$

Step-by-step explanation:

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8 0

3 years ago

Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value.

Blizzard [7]

First,

We are dealing with parabola since the equation has a form of,

$y=ax^2+bx+c$

Here the vertex of an up - down facing parabola has a form of,

$x_v=-\dfrac{b}{2a}$

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$a=-5,b=-10, c=6$

Plug them in vertex formula,

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We now got a point parabola vertex with coordinates,

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From here we emerge two rules:

If $a$ then vertex is max value
If $a>0$ then vertex is min value

So our vertex is minimum value since,

$a=-5\Longleftrightarrow a$

Hope this helps.

r3t40

7 0

3 years ago