Hewo do u know fractions because I am dying from it T-T 1/2+___=7/6 Help T-T
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Answer:
Step-by-step explanation:
By drawing the point (-3,-1) in the coordinate plane we find the graph shown below. Since there are 10 points between points A and B, we need to start at point A and then we have to move 11 units either to the right, to the left, up, or down .
1. MOVING TO THE RIGHT:
From point A, move 11 units horizontally to the right to come to point B:
(-3+11, -1) = (8, -1)
2. MOVING TO THE LEFT:
From point A, move 11 units horizontally to the left to come to point B:
(-3-11, -1) = (-14, -1)
3. MOVING UPWARD:
From point A, move 11 units vertically upward to come to point B:
(-3, -1+11) = (-3, 10)
4. MOVING DOWNWARD:
From point A, move 11 units vertically downward to come to point B:
(-3, -1-11) = (-3, -12)
So this are the basic movements you can get to find point B. You also can move diagonally upwards or downwards in whose case you would find other four points. The graph below shows a red point which is A, and the other points are in black color and represent B.
The speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.
A star moving away from the observer (say on Earth) will have its emitted light red-shifted (move to lower frequency), i.e., the spectrum moving to left if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.
A star moving towards the observer (say on Earth) will have its emitted light blue-shifted (move to higher frequency), i.e., the spectrum moving to the right if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.
A star moving perpendicular to the observer (say on Earth) will have its emitted light will no change with respect to the spectrum of the stationary star.
These are due to the Doppler effect, the equation of frequency detected by the observer as
where
, v the relative velocity of the moving source (the star here), f^s is the frequency of light emitted by the source.
Hence the answer is the speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.
To learn more about frequency click here brainly.com/question/26177128
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