Answer:
(8,-4)
Step-by-step explanation:
The difference between A and M is 2.5x and -4y
so B would be 5.5+2.5 and 0-4
(8,-4)
First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
Answer:
Step-by-step explanation:
2x = 3y + 1/2
standard : Ax + By = C
2x = 3y + 1/2....multiply everything by 2 to get rid of the fractions
4x = 6y + 1 ....subtract 6y from both sides
4x - 6y = 1 <==
slope intercept : y = mx + b
2x = 3y + 1/2....subtract 1/2 from both sides
2x - 1/2 = 3y....divide everything by 3
2/3x - 1/6 = y...rearrange
y = 2/3x - 1/6 <===
(7,0), (-7,0), (0,7), (0,-7)
80% = 6 in
100%=?
100/x 80/6 (proportional relationship)
then cross multiply
600 = 80x
600/80= 7.5
x=7.5
