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guapka [62]
2 years ago
5

2x-y=4 X and y intercept?

Mathematics
2 answers:
kobusy [5.1K]2 years ago
8 0
The x intercept is (2,0) and the y intercept is (0,-4)! I hope this helps
s344n2d4d5 [400]2 years ago
7 0

Answer:

x=2  y=-4

Step-by-step explanation:

2x-y=4   solve for x

2x-0=4

2x=4+0

2x=4 . divide both sides by 2

x=2

2x-y=4 .  solve for y

0-y=4

-y=4 . divide both sides by -1

y=-4

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triangle ABC is reflected across the y-axis and then dilated by a factor of 1/2 centered at the origin. which statement correctl
Nadya [2.5K]

Answer:

Step-by-step explanation:

The reflection preserves the side lengths and angles of triangle ABC. The dilation preserves angles but not side lengths.

5 0
2 years ago
Two ways to simplify 2(5ft + 3ft)
strojnjashka [21]
Either you can use distributive property or you can add up the numbers in the brackets. 
Hopefully that helped! :) 
6 0
3 years ago
What is the measure of A? And B
sladkih [1.3K]

Answer:

A = 72°

B = 108°

Step-by-step explanation:

5y - 3 = 3y + 27

5y - 3y = 27 + 3

2y = 30

y = 30/2

y = 15

A = 5y - 3

A = 5(15) - 3

A = 75 - 3

A = 72°

A + B = 180°

72° + B = 180°

B = 180° - 72°

B = 108°

7 0
3 years ago
Read 2 more answers
23.13 plus what gives you 39.35
vredina [299]

Answer:69

Step-by-step explanation:nice

6 0
3 years ago
Read 2 more answers
What percentage of the semi circle is shaded? <br>​
mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%

r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\% (1)

Where:

  • A_{h} - Area of the half cross, in square centimeters.
  • A_{s} - Area of the semicircle, in square centimeters.
  • r - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100

r \approx 23.606\,\%

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

3 0
2 years ago
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